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Brut [27]
3 years ago
11

Read and solve each problem.

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

a) How many donuts did Jane buy>

b) A box of donuts contains 12 pieces, and Jane bought 24 boxes for Jannea's birthday.

c) Multiplication

d) ???

e) 288

Step-by-step explanation:

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Two angles are supplementary if the sum of their measures is 180 degrees. find two supplementary angles such that the smaller is
kaheart [24]
If the larger angle is x and the smaller angle is y, y=(1/2)x+30 since it's 30 more than 1/2 of it. In addition, x+y=180 since they are supplementary. Plugging y=(1/2)x+30 into that, we get x+x/2+30=180=1.5x+30. Subtracting 30 from both sides, we get 1.5x=150. Next, we can divide both sides by 1.5 to get x=100 and y=(1/2)*100+30=50+30=80
8 0
3 years ago
Need help asap pls!!!
lisabon 2012 [21]

Answer:

16

Step-by-step explanation:

According to the given description, PS is the mid segment of the \triangle TQR

Therefore by Mid-segment Theorem:

PS = \frac{1}{2}  QR \\  \\ PS = \frac{1}{2}   \times 32 \\  \\ PS =16 \:

3 0
3 years ago
Convert 5 over 8 to a decimal and tell whether it terminates or repeats.
AURORKA [14]

Answer: The answer is D. .625

Step-by-step explanation: It terminates, meaning that it doesn't repeat itself

7 0
3 years ago
A treatment is administered to a sample of n = 9 individuals selected from a population with a mean of µ = 80 and a standard dev
stepan [7]

Answer:

a) M =82

Step-by-step explanation:

Let´s study this as a Normal distribution.

As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))

where

X = mean for the taken sample = What we want to know in this problem

μ = Total population mean =80

sd= standard deviation= 12

n = sample size=9

So in this case z=( X-80)/(12/sqr(9))= (X-80)/4

also we know that the effect size taken by the machine is 0.5, which is the same as the z-score

so...

0.5 = (X-80)/4 => 0.5*4 = X-80

2+80 = X

X = 82

4 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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