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tatuchka [14]
2 years ago
13

In the middle school band, there are 5 flutes for every 2 tubas. Write the ratio of flutes to tubas in three different ways.

Mathematics
2 answers:
fredd [130]2 years ago
7 0

Answer:

2/5 ; 2 to 5; 2:5

5/2 ; 2 to 5; 2:5

5/2 ; 5 to 2; 5:2

2/5 ; 5 to 2; 5:2

Step-by-step explanation:

suter [353]2 years ago
5 0
5;2 , 5 to 2 , and 5/2(fraction)
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___H2 + ___Br2 → ___HBr
Vaselesa [24]

Answer:H2+Br2-->2HBr

Step-by-step explanation:

The amount of atoms on the left side must be equal to the amount of atoms on the right side for each element.

On the left you got 2xH and 2xBr.

This means you must have the same amount on the right.

2HBr =2xH + 2xBr

3 0
3 years ago
The radius of a circle is 58 centimeters. enter the circumference of the circle
Zanzabum

Answer:

C = 364.24

Step-by-step explanation:

Comment

The circumference and the radius are related to one another. The constant relating them is pi which is a fixed number of 3.14 The formula for the circumference is C = 2*pi * r

Givens

pi = 3.14

r = 58 cm

Circumference = ?

Formula

C = 2*pi * r

C = 2 * 3.14 * 58

C = 364.24

5 0
2 years ago
Two thirds of a blueberry pie is left in
Sonja [21]
1/9 of the original pie is each slice
7 0
3 years ago
7. Find the width of the rectangular prism when the
ludmilkaskok [199]
I would say the width is 7 without having a picture.
6 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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