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kiruha [24]
3 years ago
9

Question 13 pls, that is the full question and there is no diagram

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0
The side lengths are ratio 5:4
250 = LW
area smaller = (4/5)L(4/5)W
= (16/25)LW
= (16/25)(250)
= 160 ft^2
insens350 [35]3 years ago
3 0
For similar figures, the ratio of areas is the square of the ratio of linear dimensions. The smaller billboard requires
.. (4/5)^2 * 250 ft^2 = 160 ft^
of material.
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kvv77 [185]

Answer:

No solution

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Step-by-step explanation:

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I need help <br><br> Circle P is below
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1. remember all of them add up equal to 360 degree.
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The New York Giants football team scored 4 touchdowns in their first game, 3 in their second game, and seven in their third game
kondaur [170]
X=4(6)+3(6)+7(6)
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What are the solutions to the quadratic equation 3(x − 4)2 = 75?
yan [13]

Answer:

x=-1 and x=9

Step-by-step explanation:

3(x-4)^{2} =75

(x-4)^{2} =\frac{75}{3}

(x-4)^{2}=25

(x-4)(x-4)=25

x^{2} -4x-4x+16=25

x^{2} -8x+16=25

x^{2} -8x+16-25=0

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7 0
3 years ago
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (
NikAS [45]

Answer:

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.

another way is

This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.

So,

(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA

Step-by-step explanation:

bran-list please

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