All categories

3 years ago

The area of a square is 36 square units. Find the perimeter of the square.

Mathematics

1 answer:

Fiesta28 [93]3 years ago

7 0

Answer:

the perimeter is 24 square unite

Step-by-step explanation:

the square root of 36 is 6

and a square has fours sides so

6 x 4 is 24

You might be interested in

I have no clue how to start this problem,plz help

Maksim231197 [3]

9514 1404 393

Answer:

109°

Step-by-step explanation:

You always start a problem by taking a careful look at the information given and how it relates to what is asked. Here, the key information is in the symbols marking the lines PQ and RS. They are parallel.

This means segments QR and PS are transversals. Marked angle 41° will be an "alternate interior angle" with angle TPQ, so angle TPQ is also 41°.

The desired angle, PTR, is an exterior angle to ΔQTP, so its measure is the sum of remote interior angles TQP (68°) and TPQ (41°). That is, ...

∠PTR = ∠TQP +∠TPQ = 68° +41°

∠PTR = 109°

6 0

2 years ago

Please show an explanation

Ber [7]

Answer:

You should go to algebraic calculator. its amazing

Step-by-step explanation:

brainliest?

4 0

2 years ago

The distance between the two points rounding to the nearest tenth (-8,-6) and (-3,-4)

Lesechka [4]

Answer:

5.4

Step-by-step explanation:

To find the distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , plug them into the following equation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d=\sqrt{(-3-(-8))^2+(-4-(-6))^2}$

Two negatives make a positive

$d=\sqrt{(-3+8)^2+(-4+6)^2}\\d=\sqrt{(5)^2+(2)^2}\\d=\sqrt{25+4}\\d=\sqrt{29}\\d=5.4$

Therefore, the distance between the two points rounded to the nearest tenth is 5.4.

I hope this helps!

3 0

2 years ago

Differentiate the function with respect to x f(x)= x^4/ x^2- 4 Show work

jeyben [28]

Answer:

Step-by-step explanation:

$f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}$

7 0

2 years ago

Solve for t. -t = 9(t-10) pls help

g100num [7]

Step-by-step explanation:

-t = 9(t-10)

-t = 9t - 90

90 = 9t + t

90 = 10t

90 ÷ 10 = t

9 = t

6 0

3 years ago