Answer:
The voltage input to the inverting terminal is 60μV
Explanation:
Given;
open-loop gain, A = 150,000
output voltage, V₀ = 15 V
voltage at the inverting input, = −40 μV = 40 x 10⁻⁶ V
The relationship between output voltage and voltage at the inverting input is given as;
Therefore, the voltage input to the inverting terminal is 60μV
Answer:
a) 0.35 W
b) 5.25 W
Explanation:
Given that
Width of the chip, W = 5 mm
The environment temperature, T(∞) = 15° C
Surface temperature, T(s) = 85° C
The initial convection heat coefficient, h1 = 200 W/m².K
The final convection heat coefficient, h2 = 3000 W/m².K
See attachment for solution
Answer:
a. 1.6 Kbytes/min
b. 10.417 Mbytes/min
Explanation:
a. The DSL modem operates at 768 Kbits/sec.
But,
8 bits = 1 byte and 1 Kbit = 1 000 bits, so that:
=
= 96 000 bytes
Therefore, the modem operates at 96 Kbytes/sec.
The byte to be received in 1 minute can be calculated thus;
Since 60 seconds = 1 minute, then:
=
= 1600
= 1.6 Kbytes/min
The modem receives 1.6 Kbytes/min
b. The USB sends 5 Gbits/sec.
But, 8 bits = 1 byte and 1 Gbit = 1000000000 bits so that:
=
= 625000000
= 0.625 Gbytes
The USB sends 0.625 Gbyte/sec.
Since 60 seconds = 1 minute, then:
=
= 10416666.67
= 10.417 Mbytes/min