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Westkost [7]
4 years ago
11

Rearrange these phrases to form an important reminder. This acronym is a reminder of the most common types of hazards or injurie

s caused by electricity.
Place the options in the correct order.


Shock


Burns


Fire


Arc Flash


Electrocution


Explosions
Engineering
1 answer:
Nastasia [14]4 years ago
7 0

BE SAFE = Burns Electrocution Shock Arc Flash Fire Explosions

Explanation:

Burn-A burn is the most common one,caused by electrical, flash or thermal contact.

Electrocution-A fatal one which mean killing by electricity and it occurs when your are in contact with a lethal amount of electrical energy

Shock-occurs when the body becomes part of an electrical circuit.Happens as a reflex action to passage of electrical current through the body

Arc Flash-In the presence of high voltage gap, there is a sudden release of electrical energy through the air.It releases heat and intense light that could cause a burn.

Fire- it results when there is a fault in wires, cords, switches, or plugs that can result to release of electrical fires.

Explosions-Electricity can ignite to release an explosive mixture of materials in the air.

Learn More

Electricity safety :brainly.com/question/7221343

Keywords : phrases, reminder, acronym, hazards, injuries, electricity

#LearnwithBrainly

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Answer:

Question 1 A 1020 Cold-Drawn steel shaft is to transmit 20 hp while rotating at 1750 rpm. Calculate the transmitted torque in lbs. in. Ignore the effect of friction. Answer with three decimal points. 60.024 Question 2 Based on the maximum-shear-stress theory, determine the minimum diameter in inches for the shaft in Q1 to provide a safety factor of 3. Assume Sy = 57 Kpsi. Answer with three decimal points. 0.728 Question 3 If the shaft in Q2 was made of ASTM 30 cast iron, what would be the factor of safety? Assume Sut = 31 Kpsi, Suc = 109 Kpsi 0 2.1 O 2.0 O 2.5 0 2.4 2.3 O 2.2

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A generator operating at 50 Hz delivers 1 pu power to an infinite bus through a transmission circuit in which resistance is igno
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Answer:

critical clearing angle = 70.3°

Explanation:

Generator operating at = 50 Hz

power delivered = 1 pu

power transferable when there is a fault = 0.5 pu

power transferable before there is a fault = 2.0 pu

power transferable after fault clearance = 1.5 pu

using equal area criterion to determine the critical clearing angle

Attached is the power angle curve diagram and the remaining part of the solution.

The power angle curve is given as

= Pmax sinβ

therefore :  2sinβo = Pm

                   2sinβo = 1

                   sinβo = 0.5 pu

                   βo = sin^{-1} (0.5) = 30⁰

also ;   1.5sinβ1 = 1

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Answer:

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Explanation:

Given;

dry unit weight of field compaction, W_d_{(field)} = 18 kN/m³

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