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defon
3 years ago
5

Factorise (x-y)^2-(x-y)^3=?

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

\left(x-y\right)^2\left(1-x+y\right)

Step-by-step explanation:

You factor out the common term first.

You should get the equation below.

\left(x-y\right)^2\left(1-\left(x-y\right)\right)

then you get rid of the negative inside\left(1-\left(x-y\right)\right)

and will be simplified to this.

\left(x-y\right)^2\left(1-x+y\right)

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Answer:

x = 3

Step-by-step explanation:

6.78x - 5.2 = 4.33x + 2.15

6.78x - 4.33x = 5.2 + 2.15

2.45x = 7.35

x = 7.35/2.45

x = 3

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<u>-TheUnknown</u><u>Scientist</u>

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3 years ago
Marisol noticed that she does not have a common factor.
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Answer:  option 2 describes best

Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.  

Step 1: (6x3 – 22x2) – (9x + 33)

Step 2: 2x2(3x – 11) – 3(3x + 11)

Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?

Marisol should realize that her work shows that the polynomial is prime.

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).

Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).

According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.

In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)

Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as

6x^3 – 22x^2 – 9x + 33 after opening the brackets.

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Step-by-step explanation:

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