Answer:
The distance between the walls is 70 m.
Step-by-step explanation:
Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is
BE ⊥ ED and CD ⊥ ED
AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m
AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.
The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°
The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°
As shown is figure attached below.
WE have to find the distance between the walls that is Length of ED
Length of ED = EA + AD
Consider the Δ AEB,
Using trigonometric ratio,

Here
, perpendicular = 30 m and base we can find.
thus,

We know 
thus, EA = 30 m
Consider the Δ AEB,
Using trigonometric ratio,

Here
, hypotenuse = 80 m and base we can find.
thus, 
We know, 
thus, Base = 40 m
AD = 40 m
Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m
Answer: There are eight steps and two methods. I will be showing you one of them. If you're wondering, I am in 7th grade. I go to K12 online school.
Step-by-step Explanation: 1. Add together the lengths of the bases. The bases are the 2 sides of the trapezoid that are parallel with one another. If you aren’t given the values for the base lengths, then use a ruler to measure each one. Add the 2 lengths together so you have 1 value.[1]
For example, if you find that the top base (b1) is 8 cm and the bottom base (b2) is 13 cm, the total length of the bases is 21 (8 cm + 13 cm = 21 cm, which reflects the "b = b1 + b2" part of the equation).
2. Measure the height of the trapezoid. The height of the trapezoid is the distance between the parallel bases. Draw a line between the bases, and use a ruler or other measuring device to find the distance. Write the height down so you don’t forget it later in your calculation.[2]
The length of the angled sides, or the legs of the trapezoid, is not the same as the height. The leg length is only the same as the height of the leg is perpendicular to the bases.
3. Multiply the total base length and height together. Take the sum of the base lengths you found (b) and the height (h) and multiply them together. Write the product in the appropriate square units for your problem.[3]
In this example, 21 cm x 7 cm = 147 cm2 which reflects the "(b)h" part of the equation.
4. Multiply the product by ½ to find the area of the trapezoid. You can either multiply the product by ½ or divide the product by 2 to get the final area of the trapezoid since the result will be the same. Make sure you label your final answer in square units.[4]
For this example, 147 cm2 / 2 = 73.5 cm2, which is the area (A).
Oh that’s so easy 6 grade math so I saw there’s no y intercept so just see where the point’s coordinates are
4/9 x 21/6 is this what you’re asking?
If so the answer is 1 5/9
Answer:
home team
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