Answer:
If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.
Step-by-step explanation:
We have,
The number of oranges purchased varies directly as the price of the oranges.
If the cost of 11 oranges is $2.35.
It is required to find the cost of 18 oranges.
As their is direct relation between number and oranges and price.
So,
The cost of 1 orange is $
.
For finding the cost of 18 oranges, multiply 18 by $ such that,
So, If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.
<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
Right 2 up 3 because when the change happens within x the opposite result happens but for vertical it remains the same . So the answer is <span>right 2, up 3</span>
f(x)−4 involves translating the graph of f(x) DOWN by 4 units.
4f(x) involves vertical stretching of the graph by a factor of 4.
