To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.
The two numbers are both 9, so its safe to say that the median is 9.
to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).
Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3
The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.
It’s what the other person said trust me :)
9514 1404 393
Answer:
a. 61
Step-by-step explanation:
The remainder theorem tells you the remainder of f(x)/(x -3) is equal to f(3). Using x=3 in the expression, we have ...
4x³ -2x² -10x +1
= ((4x -2)x -10)x +1
= ((4·3 -2)(3) -10)(3) +1 = (10·3 -10)(3) +1 = 20·3 +1
= 61
The remainder from division by (x -3) is 61.
Answer:
N= -2
Step-by-step explanation:
N+10=8
-10= -10
N= -2
To determine the coordinates of the midpoints of a line segment, get the average of the both the abscissas and ordinates. In this example, the average of the abscissas is 22 and that of the ordinates is -4. Thus, the midpoint is (22, -4).
