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3 years ago

The ancient Greeks were able to construct a perpendicular bisector for a

Mathematics

1 answer:

Archy [21]3 years ago

6 0

Answer:

True

Step-by-step explanation:

The answer is "True". Let me explain.

Let's say that we have a line segment which we will call AB, construct a perpendicular bisector. The following steps will be taken;

1) Draw a semi circle with its centre at point A and passing through point B.

2) Draw a semi circle with its centre at point B and passing through point A.

3) The two semicircles will intersect at two points with one being above and the other being below the straight line segment AB. Now, a line will have to be drawn that passes through those two intersecting points. This drawn line is called the perpendicular bisector for line segment AB.

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B. What are the second and third terms of this arithmetic sequence? 80, 페, 페, 125,...........

nataly862011 [7]

The 2nd and 3rd term of an AP is found to be (a₂ = 95) and (a₃ = 110).

<h3>What is the sequence of AP arithmetic progression?</h3>

In Arithmetic Progression, the difference between the two numerical orders is a fixed number (AP). Arithmetic Sequence is another name for it.

We'd come across a few key concepts in AP that had been labeled as:

The first term (a)
Common difference (d)
Term nth (an)
The total of first n terms (Sn)

As shown below, the AP can also be referred to in terms of common differences.

The following is the procedure for evaluating an AP's n-th term: an = a + (n − 1) × d
The arithmetic progression sum is as follows: Sn = n/2[2a + (n − 1) × d].
Common difference 'd' of an AP: d = a2 - a1 = a3 - a2 = a4 - a3 = ...... = an - an-1.

Now, the given sequence is; 80, _, _, 125.

The series comprises of four given terms.

Let the first term be 'a₁' = 180.

The second term be 'a₂'.

The third term be 'a₃'.

And, the fourth term is 'a₄' = 125.

Use the nth term formula to find the common difference 'd'.

n-th term: an = a + (n − 1) × d

a₄ = a + (n - 1)d

125 = 80 + (4 - 1)d

45 = 3d

d = 15

Thus, the common difference is 15.

The second term is calculated as;

a₂ = a₁ + d

a₂ = 80 + 15

a₂ = 95.

The third term is estimated as;

a₃ = a₂ + d

a₃ = 95 = 15

a₃ = 110

Therefore, the 2nd and third term of an AP is computed as 95 and 110.

To know more about Arithmetic Sequence, here

brainly.com/question/24989563

#SPJ4

8 0

1 year ago

Find the square root of the decimal no 2.56

Alenkasestr [34]

Consider this decimal as a fraction.

We have:

$\sqrt{ \frac{256}{100} }$

We now can take the square root of the numerator and the denominator separately for a result of 16/10, or 1.6.

5 0

3 years ago

Someone Help me pleaseee☹️

garri49 [273]

Answer:

I need help too...............