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3 years ago

10

The ancient Greeks were able to construct a perpendicular bisector for a

1 answer:

Archy [21]3 years ago

6 0

Answer:

True

Step-by-step explanation:

The answer is "True". Let me explain.

Let's say that we have a line segment which we will call AB, construct a perpendicular bisector. The following steps will be taken;

1) Draw a semi circle with its centre at point A and passing through point B.

2) Draw a semi circle with its centre at point B and passing through point A.

3) The two semicircles will intersect at two points with one being above and the other being below the straight line segment AB. Now, a line will have to be drawn that passes through those two intersecting points. This drawn line is called the perpendicular bisector for line segment AB.

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What is the midpoint of segment JK shown in the graph?

Bingel [31]

Use midpoint formula
(-4+5)/2 , (2+(-3))/2
(1/2, -1/2)

3 0

3 years ago

Write an equivalent expression using distributive property and simplify for each question

Akimi4 [234]

Answers:

Here we have to solve each expression applying the distributive property (when necessary) and taking into account the rules related to algebraic addition:

A) $2x+10x=12x$

B) $-4(3x-10)+5(2-6x)=-12x+40+10-30x=-42x+50$

Factoring the result with $2$ as a common factor:

$-42x+50=2(-21x+25)=2(25-21x)$

C) $2(x-4)+x=2x-8+x=3x-8$

D) $-3-7(3-4x)+8x=-3-21+28x+8x=36x-24$

Factoring the result with $12$ as a common factor:

$36x-24=12(3x-2)$

7 0

3 years ago

Anusha needs to find a rectangular container large enough to hold a volume of 130 in.3. Which container should she use?

leonid [27]

Option C

Container with the dimensions 3 by 5 by 10 inches has a volume of 150 cubic inches, which is large enough to hold a volume of 130 cubic inches

<em><u>Solution:</u></em>

Anusha needs to find a rectangular container large enough to hold a volume of 130 cubic inches

The volume of rectangular container is:

$volume = length \times width \times height$

<em><u>Option A</u></em>

Container with the dimensions 2 by 5 by 10 inches

Therefore, volume is given as:

$Volume = 2 \times 5 \times 10 = 100$

Thus volume is 100 cubic inches

<em><u>Option B</u></em>

Container with the dimensions 3 by 4 by 10 inches

Therefore, volume is given as:

$Volume = 3 \times 4 \times 10 = 120$

Thus volume is 120 cubic inches

<em><u>Option C</u></em>

Container with the dimensions 3 by 5 by 10 inches

Therefore, volume is given as:

$Volume = 3 \times 5 \times 10 = 150$

Thus volume is 150 cubic inches

<em><u>Option D</u></em>

Container with the dimensions 4 by 2 by 10 inches

Therefore, volume is given as:

$Volume= 4 \times 2 \times 10 = 80$

Thus volume is 80 cubic inches

Thus Container with the dimensions 3 by 5 by 10 inches has a volume of 150 cubic inches, which is large enough to hold a volume of 130 cubic inches

4 0

3 years ago

Read 2 more answers

HELLLLPPPPP PLZZZZZZZ ITS TIMED An 8” candle burns at a rate of one-third of an inch per hour and an 11” candle burns at 1” per

Diano4ka-milaya [45]

It will be 3 hours until they are the same hight

7 0

4 years ago

What is the equation of the line that passes through (4, -1) and (-2, 3)?

Mrac [35]

Answer:

2x + 3y - 5 = 0

Step-by-step explanation:

(4 , -1) & (-2,3)

$Slope =\frac{y_{2}-y_{1}}{x_{2}-x_1}}\\\\=\frac{3-[-1]}{-2-4}\\\\=\frac{3+1}{-6}\\\\=\frac{4}{-6}\\\\=\frac{-2}{3}$

m = -2/3; (4 , -1)

y - y1 = m(x - x1)

$y - [-1]= \frac{-2}{3}(x-4)\\\\y + 1 =\frac{-2}{3}x -4*\frac{-2}{3}\\\\y + 1 =\frac{-2}{3}x+\frac{8}{3}$

Multiply the equation by 3

3y + 3 = -2x + 8

3y = -2x + 8 - 3

3y = -2x + 5

2x + 3y - 5 = 0

7 0

4 years ago