Answer:
a)
, b)
, c)
, d)
, e) ![T_{H} = 25.129\,^{\circ}C](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%2025.129%5C%2C%5E%7B%5Ccirc%7DC)
Explanation:
a) The coefficient of performance of the reversible refrigeration cycle is:
![COP_{R} = \frac{T_{C}}{T_{H}-T_{C}}](https://tex.z-dn.net/?f=COP_%7BR%7D%20%3D%20%5Cfrac%7BT_%7BC%7D%7D%7BT_%7BH%7D-T_%7BC%7D%7D)
![10 = \frac{419.67\,R}{T_{H}-419.67\,R}](https://tex.z-dn.net/?f=10%20%3D%20%5Cfrac%7B419.67%5C%2CR%7D%7BT_%7BH%7D-419.67%5C%2CR%7D)
The temperature of the hot reservoir is:
![10\cdot T_{H} - 4196.7 = 419.67](https://tex.z-dn.net/?f=10%5Ccdot%20T_%7BH%7D%20-%204196.7%20%3D%20419.67)
![T_{H} = 461.637\,R](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%20461.637%5C%2CR)
![T_{H} = 1.967\,^{\circ}F](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%201.967%5C%2C%5E%7B%5Ccirc%7DF)
b) The coefficient of performance is:
![COP_{R} = \frac{273.15\,K}{303.15\,K-273.15\,K}](https://tex.z-dn.net/?f=COP_%7BR%7D%20%3D%20%5Cfrac%7B273.15%5C%2CK%7D%7B303.15%5C%2CK-273.15%5C%2CK%7D)
![COP_{R} = 9.105](https://tex.z-dn.net/?f=COP_%7BR%7D%20%3D%209.105)
c) The temperature of the hot reservoir can be determined with the help of the following relation:
![\frac{Q_{C}}{Q_{H}-Q_{C}} = \frac{T_{C}}{T_{H}-T_{C}}](https://tex.z-dn.net/?f=%5Cfrac%7BQ_%7BC%7D%7D%7BQ_%7BH%7D-Q_%7BC%7D%7D%20%3D%20%5Cfrac%7BT_%7BC%7D%7D%7BT_%7BH%7D-T_%7BC%7D%7D)
![\frac{500\,BTU}{600\,BTU-500\,BTU} = \frac{479.67\,R}{T_{H}-479.67\,R}](https://tex.z-dn.net/?f=%5Cfrac%7B500%5C%2CBTU%7D%7B600%5C%2CBTU-500%5C%2CBTU%7D%20%3D%20%5Cfrac%7B479.67%5C%2CR%7D%7BT_%7BH%7D-479.67%5C%2CR%7D)
![5 = \frac{479.67\,R}{T_{H}-479.67\,R}](https://tex.z-dn.net/?f=5%20%3D%20%5Cfrac%7B479.67%5C%2CR%7D%7BT_%7BH%7D-479.67%5C%2CR%7D)
![5\cdot T_{H} - 2398.35 = 479.67](https://tex.z-dn.net/?f=5%5Ccdot%20T_%7BH%7D%20-%202398.35%20%3D%20479.67)
![T_{H} = 575.604\,R](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%20575.604%5C%2CR)
![T_{H} = 115.934\,^{\circ}F](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%20115.934%5C%2C%5E%7B%5Ccirc%7DF)
d) The coefficient of performance is:
![COP_{R} = \frac{489.67\,R}{559.67\,R-489.67\,R}](https://tex.z-dn.net/?f=COP_%7BR%7D%20%3D%20%5Cfrac%7B489.67%5C%2CR%7D%7B559.67%5C%2CR-489.67%5C%2CR%7D)
![COP_{R} = 6.995](https://tex.z-dn.net/?f=COP_%7BR%7D%20%3D%206.995)
e) The temperature of the cold reservoir is:
![8.9 = \frac{268.15\,K}{T_{H}-268.15\,K}](https://tex.z-dn.net/?f=8.9%20%3D%20%5Cfrac%7B268.15%5C%2CK%7D%7BT_%7BH%7D-268.15%5C%2CK%7D)
![8.9\cdot T_{H} - 2386.535 = 268.15](https://tex.z-dn.net/?f=8.9%5Ccdot%20T_%7BH%7D%20-%202386.535%20%3D%20268.15)
![T_{H} = 298.279\,K](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%20298.279%5C%2CK)
![T_{H} = 25.129\,^{\circ}C](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D%2025.129%5C%2C%5E%7B%5Ccirc%7DC)
I think the answer would be A if its wrong I’m sorry
Answer:
Answer for the question is given in the attachment .
Explanation:
Answer:3.47 m
Explanation:
Given
Temperature(T)=300 K
velocity(v)=1.5 m/s
At 300 K
![\mu =1.846 \times 10^{-5} Pa-s](https://tex.z-dn.net/?f=%5Cmu%20%3D1.846%20%5Ctimes%2010%5E%7B-5%7D%20Pa-s)
![\rho =1.77 kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D1.77%20kg%2Fm%5E3)
And reynold's number is given by
![Re.=\frac{\rho v\time x}{\mu }](https://tex.z-dn.net/?f=Re.%3D%5Cfrac%7B%5Crho%20v%5Ctime%20x%7D%7B%5Cmu%20%7D)
![5\times 10^5=\frac{1.77\times 1.5\times x}{1.846\times 10^{-5}}](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E5%3D%5Cfrac%7B1.77%5Ctimes%201.5%5Ctimes%20x%7D%7B1.846%5Ctimes%2010%5E%7B-5%7D%7D)
![x=\frac{5\times 10^5\times 1.846\times 10^{-5}}{1.77\times 1.5}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Ctimes%2010%5E5%5Ctimes%201.846%5Ctimes%2010%5E%7B-5%7D%7D%7B1.77%5Ctimes%201.5%7D)
x=3.47 m