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solniwko [45]
4 years ago
12

During experiments on laser etching of microchips for IBM, a nuclear engineer places a discshaped sample 5 mm in diameter in a v

acuum chamber with surface temperature of 300 K. A 500 mW laser is then used to irradiate the sample uniformly. The sample surface can be considered ‘gray’ with an emissivity of 0.9 and can be considered ‘thin’ so that the disk temperature is uniform. In addition, a non-participating gas at a temperature of 27⁰C is used to cool the sample with a convection coefficient of 50 W/(m2K). Find the steady-state temperature of the disk

Engineering
1 answer:
Andru [333]4 years ago
7 0

Answer:

Steady state temperature is approximately 801K

Explanation:

Detailed explanation and calculation is shown in the images below.

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Given a reservoir watershed of 22 square miles, and assuming a
saveliy_v [14]

Answer:

308 acre-ft of water

Explanation:

Given:

Area of the watershed = 22 square miles

Depth of Rainfall = 0.75 in =\frac{\textup{0.75}}{\textup{12}}=0.0625 ft

Percentage rainfall falling in reservoir as runoff = 35%

Now,

1 square mile = 640 acre

Thus,

22 square miles = 22 × 640 = 14,080 acres

Thus,

The total volume of rainfall = Area of watershed × Depth of the rainfall

or

The total volume of rainfall = 14,080 acres × 0.0625 ft = 880 acre-ft

also,

only 35% of the total rainfall is contributing as runoff

thus,

Runoff = 0.35 × 880 acre-ft = 308 acre-ft of water

8 0
3 years ago
Scientists learn more about the natural world through investigation. This involves identifying a problem, researching related in
mars1129 [50]

Answer:

This shows that the technological designs are similar to the scientific investigation processes.

Explanation:

Scientists carry out scientific investigations and discoveries. They learn from their environment by investigating the natural world. The scientist investigates by problem identification, research the related information, designing and conceptualizing, investigating and analyzing the results and deriving out conclusions.

Similarly the engineers follow the same step and provide solutions to the problems of the society through their products and technological designs. The engineers first identify the need of the product, design and implement the design to provide solution and then evaluate the solution. These are the similar steps that an engineer follow in a technological design of a product or a solution.

3 0
3 years ago
A road has a crest curve, where the PVI station is a 71 35. The road transitions from a 2.1% grade to a -3.4% grade. The highest
sveticcg [70]

Answer:

Stat PVC = Stat(82+98.5)

Stat PVT = Stat(59+71.5)

Explanation

PVI = 71 + 35

Let G1 = Grade 1; G2 = Grade 2

G1 = +2.1% ; G2 = -3.4%

Highest point of curve at station = 74 + 10

General equation of a curve:

y = ax^{2} +bx+c\\dy/dx=2ax+b\\

At highest point of the curve dy/dx=o

2ax+b=0\\x=-b/2a\\x=G1L/(G2-G1)\\x=L/2 +(stat 74+10)-(stat 71+35)\\x=L/2 + 275

-G1L/(G2-G1) = (L/2 + 275)/100\\L = -2327 ft\\Station PVC = Stat(71+35)+(-2327/2)\\\\Stat PVC = 7135-1163.5\\Stat PVC = Stat(82+98.5)\\

Station PVT

Station PVT = Stat PVI + (L/2)\\Station PVT = Stat(71+35)+(-2327/2)\\Station PVT = 7135-1163.5\\Stat PVT = Stat(59+71.5)

3 0
3 years ago
Visual interpretations when driving are two things: first, what the driver sees around him or her passively, so it is what the e
Phoenix [80]

Answer:

A. How the driver understands and processes the things his or her eyes receive.

Explanation:

When driving, visual interpretation occurs in two things;

  • What the driver sees around him or her passively, mainly what is received by the eye
  • How the driver understands and processes the things his or her eyes receive

Proper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.

8 0
3 years ago
(2 points) A perfectly mixed aeration pond with no recycle serves as the biological reactor for a small community. The pond rece
FromTheMoon [43]

Answer:

a)  t = 165 days

b) 9.9 kg/day

Explanation:

Given data:

final lelvel of BOD is 20 mg/l

Ks = 100 mg BOD/L,

kd = 0.10 day-1 ,

μm = 1.6 day-1 ,

Y = 0.60 mg SS/mg BOD

a) we know that

c_{out} = \frac{c_{in}}{1 + kt}

20 = \frac{350}{1 + 0.1 t}

solving for t

t  =  165 days

b) mass of microbes = Q(mlD) × C(mg/l)

= 30\times 10^{-3} (350-20) = 9.9 kg/day

3 0
3 years ago
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