Answer:
bus = 43
van 12
Step-by-step explanation:
This can be solved using simultaneous equations
Let v represent the number of students that a van carries
Let b represent the number of students that a bus carries
the following equations can be derived from the question
3v + 2b = 122 eqn 1
5v + 3b = 189 eqn 2
Multiply eqn 1 by 5 and eqn 2 by 3
15v + 10b = 610 eqn 3
15v + 9b = 567 eqn 4
Subtract equation 4 from 3
b = 43
Substitute for b in equation 1
3v + 2(43) = 122
solve for v
v = 12
Answer:
Total cost=$25
Step-by-step explanation:
We can derive two expressions as follows;
Total cost for the First shipping company=Medium box charges+total additional charges
where;
Medium box charges=$20
Total additional charges=Charges per pound×number of additional pounds (n)
Total additional charges=1×n=n
replacing;
Total cost for the First shipping company=20+n....equation 1
Total cost for the second shipping company=Medium box charges+total additional charges
where;
Medium box charges=$15
Total additional charges=Charges per pound×number of additional pounds (n)
Total additional charges=2×n=2 n
replacing;
Total cost for the First shipping company=15+2 n....equation 2
Equating equation 1 and equation 2
15+2 n=20+n
2 n-n=20-15
n=5
Replace the value for n in equation 2
Total cost for the First shipping company=15+2 n....equation 2
Total cost=15+(2×5)=$25
The first term (a) is - 18
You add 5 to get to the next term. Or you can solve it by taking any 2 consecutive terms and find their difference.
Formula
d = t4- t3
Givens
t4 = - 3
t3 = - 8
Solution 1
d = t4 - t3 Substitute
d = -3 - ( - 8) Remove the brackets
d = -3 + 8 Combine
d = 5 Difference
Remark
Find the general formula
tn = - a + (n - 1)d Substitute
So term 20 = Example
t20 = -18 + (20 - 1)*5 Combine the inside of the brackets. Remove the brackets
t20 = - 18 + 19*5 Combine 19 and 5
t20 = -18 + 95 "Subtract"
t20 = 77 Answer
Answer:
A = 1500
3 years = $18,644.48
30 years = $132,032.78
Step-by-step explanation:
