Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³
Answer:

Explanation:
A precipitate of calcium carbonate is formed when an aqueous solution of sodium carbonate reacts with aqueous calcium chloride . Balanced equation of this reaction ,
(↓)
This reaction takes place when both reactants present in aqueous conditions, while calcium chloride precipitate separated from aqueous solution by filtration of an aqueous solution. This filtration of precipitate formed in the reaction left behind the residues aqueous solution .
Answer:
3.98g
Explanation:
Given parameters:
Number of molecules = 1.2 x 10²⁴ molecules
Unknown:
Mass of H₂ = ?
Solution:
To find the mass of this molecule, we use the expression below:
Mass = number of moles x molar mass
Molar mass of H₂ = 2(1) = 2g/mol
6.02 x 10²³ molecules are contained in 1 mole of a substance
So; 1.2 x 10²⁴ molecules will have
= 1.99 moles of H₂
Mass of H₂ = 1.99 x 2 = 3.98g
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