Answer:
C
Explanation:
it is the correct binding type.
The correct answer is option B, that is, add 1.46 grams of NaCl to 250 milliliters of H₂O.
First there is a need to find the moles of NaCl in 250 ml of 0.10 M NaCl,
Moles of NaCl = molarity × volume = 0.10 M × (250/1000L) = 0.025 mol
The corresponding mass of NaCl is,
Mass of NaCl = moles × molar mass = 0.025 mol × 58.5 g/mol = 1.46 g
Thus, there is a need to dissolve 1.46 grams of NaCl solid into 50 ml of H₂O and dilute to 250 ml.
Answer:
52.2g of KCl would be left
The mass of KCl will remain despite the solution is been heated
Explanation:
When you are heating a solution, just the solvent (In this case, water), will be evaporated and, in theory, the mass of KCl will remain despite the solution is been heated.
Now, the mass of KCl that you can obtain from 350mL of a 2.0M solution will be:
<em>Moles KCl:</em>
350mL = 0.350L * (2.0mol / L) = 0.700 moles
<em>Mass KCl -Molar mass: 74.55g/mol-:</em>
0.700mol * (74.55g/mol) = 52.2g of KCl would be left
<span>a. They produce ions when dissolved in water.
acids in water
</span>
<span>HA + H2O --> H3O+ + A-</span>
HA --> H+ + A<span>-</span>
bases
B + H2O --> OH - + BH+
