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2 years ago

Find the area of the figure.

Mathematics

2 answers:

trapecia [35]2 years ago

5 0

If i’m not mistaken it should be 55 because if you find the area of the whole triangle and subtract the mini rectangle you should get the shape

Inga [223]2 years ago

5 0

I’m pretty sure the answer is 15. this is because i split the triangle into 2 parts, then i multiplied 5x4 for the first triangle which equals 20, but then u have to divide it by 2 bc the formula for a triangle is A=1/2 (b x h) so then the answer for the first triangle is 10. now you have to do it to the other little triangle which gives u 5. at this point you have to add 10+5 which gives you 15. therefore the answer for this question is 15. i hope this helps!

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USING OLDER BROS ACC THIS IS HOW MUCH I NEED HELP PLEASE BE QUICK--------------------

lesya692 [45]

Given:
Rectangle: 320 x 190
triangle: base: 305
I'm assuming that the unit measure is in miles.

I found a map of Nevada and I figured that the length of the rectangle is serving as the height of the triangle.

Area of the rectangle = Length * width
A = 320 mi x 190 mi
A = 60,800 sq. mi.

Area of a triangle = (height * base) / 2
A = (320 mi x 305 mi) / 2
A = 97,600 sq. mi / 2
A = 48,800 sq. mi.

Total Area = 60,800 + 48,800 = 109,600 square miles.

4 0

3 years ago

Plzzz help....I am timed...There will be a picture provided....You will get 30 points!!! MATHH

xxMikexx [17]

Answer:

It should be the last one, She made a sign error when multiplying.

3 0

2 years ago

Read 2 more answers

A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3

AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

$x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km$

Now, we can find the time when the trains will be 1520 km apart:

$1520 km = (x_{1} + 240 km) + x_{2}$

Where 1 is for the cargo train and 2 is for the passenger train.

$1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}$

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

$1520 km = (v_{1}*t + 240 km) + v_{2}t$

$t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h$

For the cargo train, it will be 1520 km apart from the passenger train at:

$t_{1} = 12 pm + 2 h + 40 min = 2:40 pm$

And for a passenger train, it will be 1520 km apart from the cargo train at:

$t_{2} = 2 pm + 2 h + 40 min = 4:40 pm$

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) The distance traveled by both trains is given by:

$x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km$

$x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km$

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!

5 0

2 years ago

Hi!! Please help me with this question. I got an answer of 63.25 but it was incorrect and need to redo it. Please also explain h

matrenka [14]

Answer:

x ≈ 63.27

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan49° = $\frac{opposite}{adjacent}$ = $\frac{EF}{DE}$ = $\frac{x}{55}$ ( multiply both sides by 55 )

55 × tan49° = x , then

x ≈ 63.27 ( to the nearest hundredth )

4 0

2 years ago

Helpppppppppppppppppppppppppppppppp

Dafna1 [17]

Answer:
1/625

Explanation:
In case of multiplication of numbers with same base, we add the powers.
This means that:
a^x * a^y = a^(x+y)

Applying this to the given, we will find that:
(5^-1) * (5^-3) = 5^(-1-3)
= 5^-4
= 1/625

Hope this helps :)

4 0

3 years ago

Read 2 more answers