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Kobotan [32]
2 years ago
8

Find the area of the figure.

Mathematics
2 answers:
trapecia [35]2 years ago
5 0
If i’m not mistaken it should be 55 because if you find the area of the whole triangle and subtract the mini rectangle you should get the shape
Inga [223]2 years ago
5 0
I’m pretty sure the answer is 15. this is because i split the triangle into 2 parts, then i multiplied 5x4 for the first triangle which equals 20, but then u have to divide it by 2 bc the formula for a triangle is A=1/2 (b x h) so then the answer for the first triangle is 10. now you have to do it to the other little triangle which gives u 5. at this point you have to add 10+5 which gives you 15. therefore the answer for this question is 15. i hope this helps!
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Why is 2/3 greater than 3/5? Explain this to an 8 year old
Dmitrij [34]

\text{Hey there!}

\bf{\frac{2}{3}=0.6\overline{6}7}\\\\ \bf{\frac{3}{5}=0.60}

\text{Reason: if you use a fraction pie chart and compare}\frac{2}{3} \text{to}\frac{3}{5}, \text{you'd see that}\frac{2}{3} \text{has more shaded areas than as for}\frac{3}{5}\text{has the least amount}

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

8 0
3 years ago
A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
8 0
3 years ago
Solve |4 - 2x| = |3x+ 2|.
andreyandreev [35.5K]

Answer:

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5 0
3 years ago
Read 2 more answers
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They are equal...1/5 is half of 2/10

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Answer:

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Complete the conversion factor: 1 gallon / ? sq ftplanation:

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