Answer:
i say c but i may bee wrong
Step-by-step explanation:
(6^2*6^(1/2))^(1/3)
(6^(5/2))^(1/3)
6^(5/6)
The first answer is exponent
And the second answer is base
What you do is get into the form
(x-h)^2+(y-k)^2=r^2
(h,k) is center
r=radis
complete the square with x and y
x^2+y^2-2x+4y-11=0
group x and y terms together
(x^2-2x)+(y^2+4y)-11=0
take 1/2 of linear coefieicnt and add postive and negative
for x^2-2x, -2/2=-1, (-1)^2=1
for y^2+4y, 4/2=2, 2^2=4
(x^2-2x+1-1)+(y^2+4y+4-4)-11=0
complete the square
(x-1)^2-1+(y+2)^2-4-11=0
add like terms
(x-1)^2+(y+2)^2-16=0
add 16 both side
(x-1)^2+(y+2)^2=16
(x-(1))^2+(y-(-2))^2=4^2
(x-h)^2+(y-k)^2=r^2
(h,k)
(1,-2)
r=4
center is (1,-2)
radius is 4 units
The correct answer is -1.
In order to solve this, we need to split into the positive and negative version of the answers. Let's start with the positive version.
2 - x < 4
-x < 2
x > -2 ----> NOTE: When we divide by -1, we have to change the direction of the sign.
Now we'll do the negative version.
2 - x > -4
-x > -6
x < 6
So we know the number must be greater than -2, but less than 6. The only number on this list that fits that is -1.
