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timofeeve [1]
2 years ago
10

The scale on a map reads 1 cm = 250 km. How far is the actual distance if the map distance measures 3.8 cm?

Mathematics
2 answers:
gogolik [260]2 years ago
5 0

Answer:

950 km

Step-by-step explanation:

1 cm = 250 km

3.8 * 250  = 950

andreev551 [17]2 years ago
5 0

Answer:

950 km

Step-by-step explanation:

\frac{1}{250} = \frac{3.8}{x}

(cross multiply)

250(3.8)= 950

(divide both sides by 1)

950/1=950

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What is 0.1 as a fraction
Inga [223]

Answer:

1/10

Step-by-step explanation:

8 0
2 years ago
A supermarket reduced the price per pound whole chicken by 20%. How many pounds of chicken can now be purchased for the amount o
nignag [31]

Answer:

25 pounds

Step-by-step explanation:

Let us assume that initially, 1 pound of whole chicken costs x.

So, initially 20 pounds of whole chicken costs 20x.

Now, the price is reduced by 20%.

That means that 1 pound of whole chicken now costs  x[1-\frac{20}{100} ]=0.8x

Therefore, with a 0.8x amount of money, we can now purchase 1 pound of the whole chicken.  

Hence, with a 20x amount of money, we can now purchase \frac{20x}{0.8x}=25 pounds of the whole chicken.

4 0
3 years ago
2/7m-1/7=3/14<br><br> Please solve showing work
lawyer [7]
(2/7)m - (1/7) = 3/14
2m/7 =(3/14) + (1/7)
2m/7 = (3/14) + 2(1/7)
here we are multiplying 2 with 1/7 to make the denominator same for addition.
2m/7 = (3/14) +(2/14)
2m/7 = (3 + 2)/14
2m/7 = 5/14
2m = (5 *7)/14
2m = 35/14
2m = 5/2
m = 5/4
m = 1.25
So the value of "m" is 1.25
7 0
3 years ago
Read 2 more answers
I need in depth help answering ​
Volgvan
What is the question
8 0
2 years ago
​Recently, a random sample of 13-18 year olds was​ asked, "How much do you currently have in​ savings?" The data in the table re
Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]

This is an example of grouped data, where a range of values is given rather than a single data point.  First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0
3 years ago
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