Estimate the values of x when y=1

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

7 0

Step-by-step explanation:

if one were to put the y value the equation they could find out what x is for a certain value of y

putting the value of y(1), we get the equation

1=4x-1

2=4x

x=0.5

the value of x when y is 1 is =0.5

NOTE: I got this explanation on brainy on someone else I am not taking the credit

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xz_007 [3.2K]

Answer:

$Center = \boxed{1}, \: \boxed{ - 2} \: ; \: Radius = \boxed{3}$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 2x + 4y - 4 = 0 \\ \\ ({x}^{2} - 2x + 1 - 1) + ( {y}^{2} + 4y + 4 - 4) - 4 = 0 \\ \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} + 4y + 4) - 9 = 0 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = 9 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = {3}^{2} \\ \\ equating \: it \: with \\ \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ \\ h = 1 \\ k = - 2 \\ r = 3 \\ \\ center = \boxed{1} \: \boxed{ - 2} \: \: radius = \boxed{3}$

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