The mass of 5.2 x 10^22 manganese atoms in grams would be 635.784 grams.
What is Avogadro's constant?
Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons</u><u>, molecules, or atoms</u> could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³ mol⁻¹. Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons, molecules, or atoms </u>could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³.
Computation of mass
Avogadro calculated that every material had 6.022 x 10^23 atoms per mole.
5.2 x 10^22 atoms of Mn would contain how many moles?
= 6.022 x 10^23 /1 x 5.2 x10^22
=11.58 moles
Mn mass equals 11.58 moles multiplied by 54.9
= 635.784 grams
You may learn more about Avogadro's constant here: brainly.com/question/15989275
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C. because i take college classes and I've did this before
Answer:
oxygen consists of 3 isotopes and carbon consists of 2 isotopes
Explanation:
oxygen: O16, O17 and O18
Carbon: C12 and C13
Latent heat of fusion for ice is 33600J/k
Heat absorbed
- k_f×m
- 31.6×33600
- 1061,740mJ
- 1061J
Therefore, 1 mole<span> of gold weighs </span>196.9665<span> grams. So, in 2.8 grams of gold we would have:</span>
(2.8 gram)(1 mole/196.9665<span> gram) = 0.0142 mole.</span>
From Avogadro's number, we know that there are approximately 6.02 x 1023<span>atoms/mole.</span>
