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Anettt [7]
3 years ago
7

Determine the mass of a billion gold (u) atoms

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
5 0
Therefore, 1 mole<span> of gold weighs </span>196.9665<span> grams. So, in 2.8 grams of gold we would have:</span>
(2.8 gram)(1 mole/196.9665<span> gram) = 0.0142 mole.</span>
From Avogadro's number, we know that there are approximately 6.02 x 1023<span>atoms/mole.</span>
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Considering particles at the subatomic level, carrying out this experiment would help to identify the metals given that: Ca has
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Answer:

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What is the most important monosaccharide on Earth?
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3 years ago
ON a meter stick, one centimeter is generally the___ a)length of the whole stick b)length of the one hundred sticks c)distance b
Elena-2011 [213]

c)distance between two of the numbered lines

Explanation:

On a meter stick, a centimeter is usually the distance between two of the numbered lines. A meter stick is a device for measuring the length of an object.

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7 0
3 years ago
Consider the following reaction and situations 1 through 10. In the spaces provided, clearly indicate the best response to each
olchik [2.2K]

Answer:

1. C. no change

2. A. increase

3. E. shift to the right

4. A. increase

5. E. shift to the right

6. A. increase

7. F. cannot be determined

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10 F. cannot be determined

Explanation:

<em>According to Le Chaterlier principle, when a reaction is in equilibrium and one of the constraints that affect reactions is applied, the equilibrium will shift so as annul the effects of the constraints.</em>

From the equation: C(s) + H2O(g) ⇌ CO(g) + H2(g),

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1. If the pressure of the system is increased, there would be no change to the system because there are equal number of moles of products and reactants.

2. If H2 concentration is decreased, the equilibrium will shift to the right and more products will be formed. Hence, the concentration of CO will increase.

3. If H2 concentration is decreased, the equilibrium will shift to the right to annul the effects of the decrease in the concentration of a product.

4. If the concentration of H2 is increased, the equilibrium will shift to the left to annul the effects of increased concentration of a product. Hence, more H2O would be formed.

5. If H2 (a product) is removed, and C (a reactant) is added, more of the products will be formed in order to annul the effects of the actions. Hence, equilibrium will shift to the right.

6. If the amount of C (a reactant) is increased, the equilibrium will shift to the right. Hence, more H2 will be formed.

7. The reaction is endothermic, hence an increase in temperature will ordinarily shift the equilibrium to the right. However, the addition of H2 (a product) is supposed to shift the equilibrium to the left. Hence, the effects of simultaneous addition of the two actions become indeterminate.

8. Since the reaction is endothermic, increase in the temperature of the system will shift the equilibrium to the right. Hence, more CO will be formed.

9. If the concentration of H2O (a reactant) is decreased and that of CO (a product) is increased, both actions lead to the equilibrium being shifted to the left.

10. Addition of catalyst to the system will only speed up the rate at which the system reach the equilibrium.

5 0
2 years ago
How many molecules are in 643.21 grams of Mg3(PO4)2?
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Answer:

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

4 0
2 years ago
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