Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
X = # dimes
y = # quarters
x+y = 20 so x = 20 - y
0.1x + 0.25y = 4.1
substitute x = 20 - y into 0.1x + 0.25y = 4.1
0.1x + 0.25y = 4.1
0.1(20 - y) + 0.25y = 4.1
2 - 0.1y + 0.25y = 4.1
0.15y = 2.1
y = 2.1 / 0.15
y = 14
x = 20 - 14 = 6
answer
Dimes: 6 coins
Quarters: 14 coins
Double check
6 + 14 = 20 coins total
6(0.1) + 14(0.25) = 0.6 + 3.5 = $4.10
The value of Mario's car after 5 years is $8,249.
<h3>What is the value of the car after 5 years?</h3>
Deprecation is when the value of an asset declines with the passage of time as a result of wear and tear.
V = 15,999 − 1,550t
V = 15,999 − 1,550(5)
V = 15,999 - 7,750
V =$8,249
To learn more about depreciation, please check: brainly.com/question/25552427
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$6.95 before tax is the total cost