Answer:
Step-by-step explanation:
This is a question on hypothesis testing.
Population mean based on 30 year average for July was 90 with
a std deviation of 2.1
Sample of 5 shows average 93.5
To check whether sample average = population average
H0: x bar =90
Ha: x bar not equal 90(Two tailed test)
Test statistic =
=3.73
Since this lies outside the range (-1.96, 1.96) we reject null hypothesis
Hence we cannot say sample mean equals 90
Answer:
Step-by-step explanation:
we know that
---> by addition angle postulate
we have
----> given problem
----> given problem
substitute in the expression above
Divide by 2 both sides
Answer:
a) 0.3270 = 32.70% probability that Christine fails the course
b) 0.3917 = 39.17% probability that she had found someone to help
Step-by-step explanation:
We have these following probabilities:
61% probability that Christine find a coach.
100 - 61 = 39% probability that Christine does not find a coach.
With a coach, a 21% probability of failing.
Without a coach, a 51% probability of failing.
a. What is the probability that Christine fails the course?
21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So
P = 0.21*0.61 + 0.51*0.39 = 0.327.
0.327 = 32.7% probability that Christine fails the course
b. Christine ends up failing the course. What is the probability that she had found someone to help?
This can be formulated by the Bayes formula:
In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.
In this question.
P(B|A) is the probability of finding a tutor given that she failed.
P(B) is the probability of finding a tutor. So P(B) = 0.61.
P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21
P(A) is the probability of failing. So P(A) = 0.327.
So
0.3917 = 39.17% probability that she had found someone to help