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telo118 [61]
2 years ago
14

Richa is in gadget for 20 days on the condition that she will receive rupees 60 for each desi work and will be fine rupees 5 for

HTC is absent if C receive rupees 7:45 in all how many days did you remain absent?​

Mathematics
1 answer:
tankabanditka [31]2 years ago
6 0

Answer: <u>Next time please try to put clear images</u>

Let he worked for x days and absent for (20-x) days.

So, according to question, he gets 60 rs for each working day and -5 for each absent days.

SO for working days he earns 60x and for absent he gave fines of (20-x)* (-5),

So, the equation will be

60x+ (20-x)*(-5)=745

60x-100+5x=745

65x-100=745

65x=845

x=845/65=13.

So, He worked only for 13 days, Now we need to calculate the number of days he was absent, so it will be 20–13=7 days.

The answer will be 7 days.

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Write the multiple of the first even number from 11 to 20​
andrew-mc [135]

Answer:

Multiples [10] - 10, 20, 30, 40, 50

Multiples [11] - 11, 22, 33, 44, and 55

<u><em>Find the Even numbers of these multiples</em></u>

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  1. <u><em>10 × 1 = 10</em></u>
  2. <u><em>10 × 2 = 20</em></u>
  3. <u><em>10 × 3 = 30</em></u>
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  • - 44 = Even
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  1. <u><em>    11 × 1 = 11</em></u>
  2. <u><em>    11 × 2 = 22</em></u>
  3. <u><em>    11 × 3 = 33</em></u>
  4. <u><em>    11 × 4 = 44</em></u>
  5. <u><em>    11 × 5 = 55</em></u>
  6. <u><em>    11 × 6 = 66</em></u>
  7. <u><em>    11 × 7 = 77</em></u>
  8. <u><em>    11 × 8 = 88</em></u>
  9. <u><em>    11 × 9 = 99</em></u>

Step-by-step explanation:

.... I messed up, sorry. I thought that 20 said 11

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