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Ugo [173]
3 years ago
11

Help me answer this question the picture is linked below. I will be reporting spam answers/one's with no effort put in.

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

I think this is right? The instructions seem a bit vague to me...

Condition A: Many

Condition B: One

Condition C: One

Condition D: Many

Condition E: Many

Condition F: One

Step-by-step explanation:

So Condition A: A rectangle with 4 right angles is going to be in many quadrilaterals because squares are also a rectangle with 4 right angles. So condition A has 2 or maybe more that I forgot about.

Condition B: A square with one side measuring 5 inches is one quadrilateral. Squares are one specific type of quadrilateral so they're probably going to go into one quadrilateral

Condition C: A rhombus can sometimes also be a square, but since in this case, it's angle is only 43°, it should be one quadrilateral.

Condition D: There are a lot of parallelograms. Just because one angle is 32°, it doesn't mean there is just one. There are rhombuses and trapezoids that have 32° angles that would be parallelograms. This one is many.

Condition E: This one was hard for me to visualize, but I'm pretty sure this one is also many. There are at least 2. One side could be 6 inches and another could be 8 inches and then, it could be vice versa, so there are probably more than one. This one is many.

Condition F: Is this even possible? I think it's one.

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3 years ago
A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 225 vinyl? glov
romanna [79]

Answer:

a)

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

b)

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

c)

p-value < .00001

d)

Reject the null hypothesis.

The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of vinyl gloves that leak viruses (population 1) is greater then the population proportion of latex gloves that leak viruses (population 2).

Sample 1 (Vinyl)

n₁= 225

Sample proportion 'ρ₁= 0.60

Sample 2 (Latex)

n₂= 225

Sample proportion 'ρ₂= 0.09

Pooled proportion: 'ρ= (x₁+x₂)/(n₁+n₂)= ( 'ρ₁ + 'ρ₂)/2= (0.60 + 0.09)/2= 0.345 ≅0.35

The hypothesis is:

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

α: 0.05

The statistic to use is a pooled Z

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

The critical region is one-tailed to the right (positive), the critical value is:

Z_{1-\alpha } = Z_{0.95} = 1.64

If Z ≥ 1.64, you will reject the null hypothesis.

If Z < 1.64, you will not reject the null hypothesis.

Z= \frac{(0.6 - 0.09) - (0}{\sqrt{0.35(1-0.35)[\frac{1}{225} + \frac{1}{225} ]} } = 11.34

Since the calculated Z- value is greater than the critical value, the decision is to reject the null hypothesis. The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

P-value approach:

p-value < .00001

If you compare with the level of signification, you reach the same decision.

I hope it helps!

8 0
3 years ago
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