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coldgirl [10]
3 years ago
9

10x10x10x10x10x10x10 in word form

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

10 times 10 or ten times ten or ten to the power of seven ( only for expontants )

Step-by-step explanation:

hope it helps :)

Vsevolod [243]3 years ago
5 0

Answer:

10,000,000

Step-by-step explanation:

ten million

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For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
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There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin
hoa [83]

Answer:

\frac{dI}{dt}=-0.00016 A/s

Step-by-step explanation:

We are given that

By ohm's law

V=IR

R=389 ohm

I=0.03 A

\frac{dV}{dt}=-0.06V/s

\frac{dR}{dt}=0.07ohm/s

We have to find rate of change of current I means \frac{dI}{dt}

Differentiate the equation w.r.t t

\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}

Substitute the values then we get

-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07

-0.06=389\frac{dI}{dt}+0.0021

-0.06-0.0021=389\frac{dI}{dt}

-0.0621=389\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s

Hence, the current I is changing at the rate=-0.00016A/s

4 0
3 years ago
Just help please need to pass
Anni [7]

Answer: \frac{1}{10}

Step-by-step explanation:

First, we need to find the common denominator

The easiest way to do this is by multiplying the two given denominators, which are 2 and 5.

2 × 5 = 10

So, our common denominator is 10. Then, multiply the numerators of the two fractions by 2 and 5. Here's why:

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Do the same thing for the other one:

\frac{1*5}{2*5} = \frac{5}{10}

Finally, subtract the two fractions to find the difference between the two times:

\frac{6}{10} -\frac{5}{10} = \frac{1}{10}

The reason we used the common denominator is because we can only add or subtract fractions if they have the same denominator.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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