Cos(θ) = -20/√((-20)^2 +(-21)^2)
.. = -20/-√841 . . . . . . . . . . . . . . . . . θ is a 4th-quadrant angle, so cos(θ) > 0
.. = 20/29
The value of the cosine is 20/29.
A) I would make the positive integer x and then form an equation.
x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6
Since the question asks for a positive integer the answer is 7.
B) two positive numbers x and y.
X - y = 3
x^2 + y^2 = 117
Use these simultaneous equations to figure out each number.
Rearrange the first equation
x = y + 3
Then substitute it into the second equation.
(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)
This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.
Use y to find x
x = y + 3
x = 6 + 3
x = 9
So the answers are x = 9 and y = 6.
It only thousand you can't rounded to ten thousand
Answer:
The average rate of change from x=0 to x=1 for f(x) is 0.
Step-by-step explanation:
We are given the function .
Now, the rate average rate of change of a function from to is given by .
As, we need the rate of change from x = 0 to x = 1.
So, we will find the values of f(0) and f(1).
i.e. i.e. f(0) = 3
and i.e. i.e. f(1) = 3
Thus, the rate of change from x=0 to x=1 is i.e. i.e. 0
Hence, the average rate of change from x=0 to x=1 for f(x) is 0.