After this answer is simplified, the answer is A) 3.9a+b
Answer:
The proof is derived from the summarily following equations;
∠FBE + ∠EBD = ∠CBA + ∠CBD
∠FBE + ∠EBD = ∠FBD
∠CBA + ∠CBD = ∠ABD
Therefore;
∠ABD ≅ ∠FBD
Step-by-step explanation:
The two column proof is given as follows;
Statement 
Reason
bisects ∠CBE Given
Therefore;
∠EBD ≅ ∠CBD Definition of angle bisector
∠FBE ≅ ∠CBA Vertically opposite angles are congruent
Therefore, we have;
∠FBE + ∠EBD = ∠CBA + ∠CBD Transitive property
∠FBE + ∠EBD = ∠FBD Angle addition postulate
∠CBA + ∠CBD = ∠ABD Angle addition postulate
Therefore;
∠ABD ≅ ∠FBD Transitive property.
The answer is
15m^2n + 4/n
Hope that helps, have a nice night or day <4
Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is 6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²
2nd answer: :
Volume of pyramid: (base area)(height)/3
Volume of pyramid: (3x²√3).(3x)/3 (because height = 3x, given)
Then Volume of pyramid= 3x³√3 unit³.
3 is the answer for the second question
and 6 for the 1st
