Question

A 3000-kg truck moving with a velocity of 25 m/s hits a 1000-kg parked car. The impact causes the 1000-kg car to be set in motion at 7 m/s. What is the velocity of the truck after the collision?

Answer 1

Answer:

v₃ = 22.67 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the quantity of linear momentum. Where momentum is conserved before and after the collision, i.e. remains the same.

The terms on the left of the equation represent the amount of linear momentum before the collision and the members on the right represent the momentum after the collision.

$(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}*v_{3})+(m_{2}*v_{4})$

where:

m₁ = mass of the truck = 3000 [kg]

m₂ = mass of the car = 1000 [kg]

v₁ = velocity of the truck before the coliision = 25 [m/s]

v₂ = velocity of the car parked = 0 (without movement)

v₃ = velocity of the truck after the collision [m/s]

v₄ = velocity of the car after the collision = 7 [m/s]

Now replacing:

$(3000*25)+(1000*0)=(3000*v_{3})+(1000*7)\\75000-7000 = 3000*v_{3}\\v_{3}=22.67 [m/s]$