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d1i1m1o1n [39]
2 years ago
10

A jet of water of cross section area and velocity v impinges normally on a stationary flat plate the mass per unit volume of wat

er ρ
by dimensional analysis determine and expression for the force f exerted by the jet against the plate.​
Physics
1 answer:
Sergio039 [100]2 years ago
4 0
<h2>F = kAρv²</h2>

Explained in the attachment !

<h3>Hope it helps you!!</h3>

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The law of reflection states that if the angle of incidence is 76 degrees, the angle of reflection is ___ degrees.
Ann [662]
Answer is 76 degrees. 

The law of reflection states that when a line is reflected on a straight plane, the angle of incidence is equal to the angle of reflection. In this case, the angle of incidence and the angle reflection are 76 degrees.
3 0
3 years ago
The mean free path of a helium atom in helium gas at standard temperature and pressure is 0.2 um.What is the radius of the heliu
ivolga24 [154]

Answer: 0.10233nm

Explanation:

The mean free path \lambda   of an atom is given by the following formula:

\lambda=\frac{RT}{\sqrt{2} \pi d^{2}N_{A}P}    (1)

Where:

\lambda=0.2\mu m=0.2(10)^{-6}m

R=8.3145J/mol.K is the Universal gas constant

T=0\°C=273.115K is the absolute standard temperature

d is the diameter of the helium atom

N_{A}=6.0221(10)^{23}/mol is the Avogadro's number

P=1atm=101.3kPa=101.3(10)^{3}Pa=101.3(10)^{3}J/m^{3} absolute standard pressure

Knowing this, let's find d from (1), in order to find the radius r of the helium atom:

d=\sqrt{\frac{RT}{\sqrt{2}\pi\lambda N_{A}P}}    (2)

d=\sqrt{\frac{(8.3145J/mol.K)(273.115K)}{\sqrt{2}\pi(0.2(10)^{-6}m)(6.0221(10)^{23}/mol)(101.3(10)^{3}J/m^{3})}}    (3)

d=2.0467(10)^{-10}m    (4)

If the radius is half the diameter:

r=\frac{d}{2}  (5)

Then:

r=\frac{2.0467(10)^{-10}m}{2}  (6)

r=1.0233(10)^{-10}m  (7)

However, we were asked to find this radius in nanometers. Knowing 1nm=(10)^{-9}m:

r=1.0233(10)^{-10}m.\frac{1nm}{(10)^{-9}m}=0.10233nm  (8)

Finally:

r=0.10233nm This is the radius of the helium atom in nanometers.

5 0
3 years ago
A solid of mass 450 kg has a volume
Andrej [43]

Answer:

0.0018

Explanation:

Given that,

Mass of a solid, m = 450 kg

Volume, V = 250 cm³ = 0.00025 m³

The density of solid is given by :

Density = mass/volume

So,

d=\dfrac{450}{250}\\\\d=1.8\ kg/cm^3

The density of water is 1000 kg/cm³.

Relative density = density of solid/density of water

d=\dfrac{1.8}{1000}\\\\=0.0018

So, the relative density of the solid is 0.0018 .

7 0
3 years ago
Calculate the pressure in a 212 liter tank containing 23.3 kg of argon gas at 25°c
NNADVOKAT [17]
First of all, let's find the number of moles of the gas.

The molar mass of argon is M_m=40 g/mol=0.40 kg/mol. Since we have m=23.3 kg of gas, the number of moles is
n= \frac{m}{M_m}= \frac{23.3 kg}{0.40 kg/mol}=58.3 mol

Now we can use the ideal gas law to calculate the pressure of the gas:
pV=nRT
where
p is the pressure
V=212 L=0.212 m^3 is the volume
n=58.3 mol is the number of moles
R=8.31 J/mol K is the gas constant
T=25^{\circ}+273=298 K is the absolute temperature

Rearranging the equation, we find
p= \frac{nRT}{V}= \frac{(58.3 mol)(8.31 J/mol K)(298 K)}{0.212 m^3}=6.81 \cdot 10^5 Pa
7 0
3 years ago
A hybrid is
Sophie [7]
The correct answer is heterozygous.
7 0
4 years ago
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