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d1i1m1o1n [39]
2 years ago
10

A jet of water of cross section area and velocity v impinges normally on a stationary flat plate the mass per unit volume of wat

er ρ
by dimensional analysis determine and expression for the force f exerted by the jet against the plate.​
Physics
1 answer:
Sergio039 [100]2 years ago
4 0
<h2>F = kAρv²</h2>

Explained in the attachment !

<h3>Hope it helps you!!</h3>

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A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 11.8 m/s directly upward.
Fantom [35]

Answer:

7.09683 m

1.20285 s

2.4057 s

11.8 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² (negative up, positive down)

From equation of motion we have

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11.8^2}{2\times -9.81}\\\Rightarrow s=7.09683\ m

The maximum height above the ground that the ball reaches is 7.09683 m

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-11.8}{-9.81}\\\Rightarrow t=1.20285\ s

Time taken to go up is 1.20285 s it will take the same time to come down so total time taken to reach the ground after it is shot is 1.20285+1.20285 = 2.4057 s

v=u+at\\\Rightarrow v=0+9.81\times 1.20285\\\Rightarrow v=11.8\ m/s

The velocity just before it hits the ground is 11.8 m/s

6 0
2 years ago
True or False: An example of an Isometric movement is a plank. please help 2 mins left!<br> PE
Anon25 [30]

Answer:

Yes

Explanation:

The plank (also called a front hold, hover, or abdominal bridge) is an isometric core strength exercise that involves maintaining a position similar to a push-up for the maximum possible time

5 0
2 years ago
Read 2 more answers
3 نقطة (نقاط)
Molodets [167]

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force <em>P</em>. Let W_P be the work done by the force <em>P</em>. Then the total work done on the block is

W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}

5 0
2 years ago
A vector makes an angle of 30° with the positive x-axis.
kkurt [141]

Answer:

W = 112.58 N-unit

Explanation:

Given:

- Force F = 10 N

- Angle Q of force with x axis: 30 degrees

- distance to be moved d = 13 units along + x axis

Find:

Work Done by the force F:

Solution:

The work by force in positive x direction can only be done if the both the direction of distance traveled and direction of force are parallel vectors. Hence we compute the component of Force F in x direction F_x:

                                       F_x = F*cos(Q)

                                       F_x = 10*cos(30)

                                       F_x = 8.66 N

        Hence,

                                  Work Done by force

                                        W = F_x * d

                                       W = 8.66 * 13

                                  W = 112.58 N-unit

5 0
3 years ago
Which statement is true regarding DC current?
Illusion [34]

I think that the answer is C)

3 0
3 years ago
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