Ask question

Ask question

All categories

2 years ago

10

A jet of water of cross section area and velocity v impinges normally on a stationary flat plate the mass per unit volume of wat

er ρ
by dimensional analysis determine and expression for the force f exerted by the jet against the plate.

1 answer:

Sergio039 [100]2 years ago

4 0

<h2>F = kAρv²</h2>

Explained in the attachment !

<h3>Hope it helps you!!</h3>

You might be interested in

The law of reflection states that if the angle of incidence is 76 degrees, the angle of reflection is ___ degrees.

Ann [662]

Answer is 76 degrees.

The law of reflection states that when a line is reflected on a straight plane, the angle of incidence is equal to the angle of reflection. In this case, the angle of incidence and the angle reflection are 76 degrees.

3 0

3 years ago

The mean free path of a helium atom in helium gas at standard temperature and pressure is 0.2 um.What is the radius of the heliu

ivolga24 [154]

Answer: $0.10233nm$

Explanation:

The mean free path $\lambda$ of an atom is given by the following formula:

$\lambda=\frac{RT}{\sqrt{2} \pi d^{2}N_{A}P}$ (1)

Where:

$\lambda=0.2\mu m=0.2(10)^{-6}m$

$R=8.3145J/mol.K$ is the Universal gas constant

$T=0\°C=273.115K$ is the absolute standard temperature

$d$ is the diameter of the helium atom

$N_{A}=6.0221(10)^{23}/mol$ is the Avogadro's number

$P=1atm=101.3kPa=101.3(10)^{3}Pa=101.3(10)^{3}J/m^{3}$ absolute standard pressure

Knowing this, let's find $d$ from (1), in order to find the radius $r$ of the helium atom:

$d=\sqrt{\frac{RT}{\sqrt{2}\pi\lambda N_{A}P}}$ (2)

$d=\sqrt{\frac{(8.3145J/mol.K)(273.115K)}{\sqrt{2}\pi(0.2(10)^{-6}m)(6.0221(10)^{23}/mol)(101.3(10)^{3}J/m^{3})}}$ (3)

$d=2.0467(10)^{-10}m$ (4)

If the radius is half the diameter:

$r=\frac{d}{2}$ (5)

Then:

$r=\frac{2.0467(10)^{-10}m}{2}$ (6)

$r=1.0233(10)^{-10}m$ (7)

However, we were asked to find this radius in nanometers. Knowing $1nm=(10)^{-9}m$ :

$r=1.0233(10)^{-10}m.\frac{1nm}{(10)^{-9}m}=0.10233nm$ (8)

Finally:

$r=0.10233nm$ This is the radius of the helium atom in nanometers.

5 0

3 years ago

A solid of mass 450 kg has a volume

Andrej [43]

Answer:

0.0018

Explanation:

Given that,

Mass of a solid, m = 450 kg

Volume, V = 250 cm³ = 0.00025 m³

The density of solid is given by :

Density = mass/volume

So,

$d=\dfrac{450}{250}\\\\d=1.8\ kg/cm^3$

The density of water is 1000 kg/cm³.

Relative density = density of solid/density of water

$d=\dfrac{1.8}{1000}\\\\=0.0018$

So, the relative density of the solid is 0.0018 .

7 0

3 years ago

Calculate the pressure in a 212 liter tank containing 23.3 kg of argon gas at 25°c

NNADVOKAT [17]

First of all, let's find the number of moles of the gas.

The molar mass of argon is $M_m=40 g/mol=0.40 kg/mol$ . Since we have $m=23.3 kg$ of gas, the number of moles is
$n= \frac{m}{M_m}= \frac{23.3 kg}{0.40 kg/mol}=58.3 mol$

Now we can use the ideal gas law to calculate the pressure of the gas:
$pV=nRT$
where
p is the pressure
$V=212 L=0.212 m^3$ is the volume
$n=58.3 mol$ is the number of moles
$R=8.31 J/mol K$ is the gas constant
$T=25^{\circ}+273=298 K$ is the absolute temperature

Rearranging the equation, we find
$p= \frac{nRT}{V}= \frac{(58.3 mol)(8.31 J/mol K)(298 K)}{0.212 m^3}=6.81 \cdot 10^5 Pa$

7 0

3 years ago

Sophie [7]

The correct answer is heterozygous.

7 0

4 years ago

Read 2 more answers