Answer:
Stop cheating in exam
Explanation:
Shame!!!!
I am sorry but I will have to refer you to the student conduct at UTA.
The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
Answer:
change in momentum, ![\Delta p=7.65 \,kg.m.s^{-1}](https://tex.z-dn.net/?f=%5CDelta%20p%3D7.65%20%5C%2Ckg.m.s%5E%7B-1%7D)
Average Force, ![F=144.3396\,N](https://tex.z-dn.net/?f=F%3D144.3396%5C%2CN)
Explanation:
Given:
angle of kicking from the horizon, ![\theta= 30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%2030%5E%7B%5Ccirc%7D)
velocity of the ball after being kicked, ![v=18 m.s^{-1}](https://tex.z-dn.net/?f=v%3D18%20m.s%5E%7B-1%7D)
mass of the ball, ![m=0.425\, kg](https://tex.z-dn.net/?f=m%3D0.425%5C%2C%20kg)
time of application of force, ![t=5.3\times 10^{-2}\,s](https://tex.z-dn.net/?f=t%3D5.3%5Ctimes%2010%5E%7B-2%7D%5C%2Cs)
We know, since body is starting from the rest
.....................(1)
![\Delta p=0.425\times 18](https://tex.z-dn.net/?f=%5CDelta%20p%3D0.425%5Ctimes%2018)
![\Delta p=7.65 \,kg.m.s^{-1}](https://tex.z-dn.net/?f=%5CDelta%20p%3D7.65%20%5C%2Ckg.m.s%5E%7B-1%7D)
Now the components:
![\Delta p_x= 7.65\times cos 30^{\circ}](https://tex.z-dn.net/?f=%5CDelta%20p_x%3D%207.65%5Ctimes%20cos%2030%5E%7B%5Ccirc%7D)
![\Delta p_x= 6.6251 \,kg.m.s^{-1}](https://tex.z-dn.net/?f=%5CDelta%20p_x%3D%206.6251%20%5C%2Ckg.m.s%5E%7B-1%7D)
similarly
![\Delta p_y= 7.65\times sin 30^{\circ}](https://tex.z-dn.net/?f=%5CDelta%20p_y%3D%207.65%5Ctimes%20sin%2030%5E%7B%5Ccirc%7D)
![\Delta p_y= 3.825 \,kg.m.s^{-1}](https://tex.z-dn.net/?f=%5CDelta%20p_y%3D%203.825%20%5C%2Ckg.m.s%5E%7B-1%7D)
also, impulse
.........................(2)
where F is the force applied for t time.
Then from eq. (1) & (2)
![F\times t=m.v](https://tex.z-dn.net/?f=F%5Ctimes%20t%3Dm.v)
![F\times 5.3\times 10^{-2}= 7.65](https://tex.z-dn.net/?f=F%5Ctimes%205.3%5Ctimes%2010%5E%7B-2%7D%3D%207.65)
![F=144.3396\,N](https://tex.z-dn.net/?f=F%3D144.3396%5C%2CN)
Now, the components
![F_x=144.3396\times cos 30^{\circ}](https://tex.z-dn.net/?f=F_x%3D144.3396%5Ctimes%20cos%2030%5E%7B%5Ccirc%7D)
![F_x=125.0018\,N](https://tex.z-dn.net/?f=F_x%3D125.0018%5C%2CN)
&
![F_y=144.3396\times sin 30^{\circ}](https://tex.z-dn.net/?f=F_y%3D144.3396%5Ctimes%20sin%2030%5E%7B%5Ccirc%7D)
![F_y=72.1698\,N](https://tex.z-dn.net/?f=F_y%3D72.1698%5C%2CN)
Answer:
You would be watching tv for 1 hour and 40 mins
Explanation:
How much time take it take for 3:50 am to 5:30