All categories

3 years ago

What te answer is to the question I do not know

Mathematics

1 answer:

pishuonlain [190]3 years ago

4 0

Hello,

10 is not a digit!
Let' a ,b ,c the 3 digits
Numbers are
10a+b
10a+c
10b+c
10b+a
10c+a
10c+b
sum = 22a+22b+22c=22(a+b+c)

sum /(a+b+c)=22

You might be interested in

26/x=-13 <br> I need a false answer and what it would equil

cupoosta [38]

Correct answer:
26 = -13x
X = -2

if you need a false answer, make up any number!

7 0

1 year ago

Pls help me ASAP plssss!!!

Nataly [62]

Answer:

7. $8

8. coupons offer deals upfront, rebates only offer them after purchase, and sales are short times to drive sales

Step-by-step explanation:

7 work. best buy: 60 - 2 = 40 40 x 4 = 160

Gamestop: 60 x 0.3 = 18 42 x 4 = 168

160 - 168 = -8

$8 dollars saved by Best Buy

7 0

3 years ago

Mr Barton was answering the problem below the question

polet [3.4K]

No the student is incorrect the answer is actually 332

4 0

3 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

Graph the inequality on the axes below.<br> 3x +y > -7

irina1246 [14]

Step-by-step explanation:

use desmos it's a graphing calculator just put in the equation

4 0

3 years ago