A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
<u>Answer:</u>
$593.26
<u>Step-by-step explanation:</u>
We know that the price of the laptop is $2500 and each year its resale value decreases by 25%. It means that 100 - 25 = 75% of the value is retained every year for the resale.
So, the resale value for 1st year = 
$1875
for 2nd year = 
$1406.25
for 3rd year = 
$1054.7
for 4th year = 
$791.01
for 5th year = 
$593.25
Or we can use the following formula to find its resale value after 5 years:
$593.26
If it is a slope formula I believe it is y= 4x-24
Which is the most appropriate to describe a quantity decreasing at a steady rate?
With a linear equation.
Answer:
27/14
Step-by-step explanation:
you can cross multiply and simplify before you start. that way it makes it a lot easier
