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3 years ago

What te answer is to the question I do not know

Mathematics

1 answer:

pishuonlain [190]3 years ago

4 0

Hello,

10 is not a digit!
Let' a ,b ,c the 3 digits
Numbers are
10a+b
10a+c
10b+c
10b+a
10c+a
10c+b
sum = 22a+22b+22c=22(a+b+c)

sum /(a+b+c)=22

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Select the correct answer.

kherson [118]

Answer:

d.2/6 has a repeating decimal form

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3 years ago

Lol I’m struggling very much

Alex73 [517]

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3 years ago

If g(x) = -2x5 - 4, find g(2).

miskamm [114]

$g(x)+-2x^5-4$

Substitute the value of x = 2 to the equation:

$g(2)=-2\cdot2^5-4=-2\cdot32-4=-64-4=-68$

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3 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B9x%2B20%3D0" id="TexFormula1" title="x^{2} +9x+20=0" alt="x^{2} +9x+20=0" ali

Hoochie [10]

Answer:

We have been given an equation $x^2+9x+20=0$

We will factorize it by middle term splitting.

Step 1: $x^2+5x+4x+20=0$

Taking common factors out by clubing first two terms ad last two terms

Step 2: $x(x+5)+4(x+5)=0$

Step 3: $(x+4)(x+5)=0$

Equating both above factors to zero as:

Step 4: $(x+4)=0\Rightarrow x=-4$

And $(x+5)=0\Rightarrow x=-5$ .

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!!! 25 POINTS!!!!

Andrei [34K]

Answer:

0.9562

Step-by-step explanation:

Binomial probability is mathematically expressed as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}$

Given that p=0.18, n=5 , is calculated as:

$P(X\leq 2)=P(0)+P(1)+P(2)\\\\={5\choose 0}0.18^0(1-0.18)^5+{5\choose 1}0.18^1(1-0.18)^4+{5\choose 2}0.18^2(1-0.18)^3\\\\=0.3707+0.4069+0.1786\\\\=0.9562$

Hence, the probability of no more than 2 successes in 5 trials is 0.9562

4 0

3 years ago