1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inysia [295]
3 years ago
11

Complete the function table.

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

B

Step-by-step explanation:

The function given is f(n) = n-3. Plug in n=0 and you will get an output - 3. Plug in n=2 and you will get an output - 1. Hence table B is the answer .

You might be interested in
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
Ill do brainliest plsss help its a unit test due in 10 minutes
Fofino [41]

Answer:

18

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I’ve tried everything.
klio [65]

Answer:

A

Step-by-step explanation:

tell me if im wrong

4 0
3 years ago
I need help solving number 17.
melisa1 [442]
Let x = amount of sales (in dollars)

The salary is $400 and there's an additional 0.06x dollars added on to get to the goal of 790. The equation is therefore

<span>400+0.06x = 790
</span>
Let's solve for x

400+0.06x = 790
<span>400+0.06x-400 = 790-400
</span>0.06x = 390
0.06x/0.06 = 390/0.06
x = 6500

The final answer is 6500

This means he must have $6,500 in sales. 
8 0
4 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
Other questions:
  • Compare using &lt;, &gt;, or =. 7 2/5___ 7 3/8
    6·1 answer
  • Charlotte is going to run a 10-kilometer race. She has trained to run 1 kilometer every 4 minutes. After she runs at this rate f
    6·2 answers
  • 40.An instrument that is inconsistent in measuring a variable would lack: trustworthiness credibility triangulation reliability
    8·1 answer
  • to find 36+29+14,joshua rewrote the expression as 36+14+29.what property did Joshua use to rewrite the expression
    10·1 answer
  • Do you believe that the US should convert to the metric system explain why or why notâ
    11·1 answer
  • Answer this true or false question please:4x-1&lt;2x+7 when x =1​
    15·1 answer
  • Which equation describes a line that has a slope of 4/5 and a y- intercept of 2/5
    15·1 answer
  • Marton finds a shirt on sale for 10% off at the department store. the original price was $20 marton also must pay the sales tax
    12·1 answer
  • What is the amount spent on each visit to the smoothie shop?
    14·1 answer
  • Pls pls pls answer I need this done before 10;50
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!