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3 years ago

Plz help me well mark brainliest if correct,.........??

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

8 0

Answer:

both A and B

Step-by-step explanation:

a's perimeter is 36 (6+6+12+12)

b's perimeter is 36 (4+4+14+14)

c's perimeter is 34 (9+9+8+8)

all the options equal to 72 sq. centi. if u multi

6*12=72

4*14=72

9*8=72

Oksanka [162]3 years ago

4 0

Answer: A

Step-by-step explanation:

Because to find the area I multiplied and got 72 then I looked up how to find them perimeter

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Use the following model.

kaheart [24]

Answer:
B.4
Step-by-step explanation:
the base is the bottom and on the bottom are what looks to be 4 bases

Hope this helps have a nice day

8 0

3 years ago

Read 2 more answers

Please help as soon as possible PLEASE

pashok25 [27]

Area of the entire rectangle $=x^2+10x+24$

Solution:

Area of the blue box = length × width

$=x\times x$

Area of the blue box $=x^2$

Area of the pink box = length × width

$=4\times x$

Area of the pink box $=4x$

Area of the green box = length × width

$=6\times x$

Area of the green box $=6x$

Area of the orange box = length × width

$=6\times 4$

Area of the orange box = 24

Total area of the rectangle $=x^2+4x+6x+24$

$=x^2+10x+24$

Area of the entire rectangle $=x^2+10x+24$

4 0

3 years ago

A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l

tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

Step(ii):-

The Empirical rule

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }$

Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = P(Z≥2.383)

= 1- P( Z<2.383)

= 1-( 0.5 -+A(2.38))

= 0.5 - A(2.38)

= 0.5 -0.4913

= 0.0087

Final answer:-

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0

3 years ago

What is √75 in simplified form? A 5√3 B 25√3 C √5 D 3√25 Answer Fast For 30 Points!

Kaylis [27]

The answer is A. 5√3

6 0

3 years ago

Read 2 more answers

You start at (10, 1). You move down 1 unit and left 7 units. Where do you end?

solmaris [256]

Translation in right or left causes the x coordinate to change while translation in up or down causes the y coordinate to change.

Moving left or down causes the coordinates to be going negative.

Moving right or up causes the coordinates to be positive.

Original point (10, 1).

Down 1 unit:

(10, 1 - 1) = (10, 0)

Left 7 units:

(10 - 7, 0) = (3, 0)

You end at (3, 0)

5 0

3 years ago