All categories

2 years ago

Circle the staement below 1530 and 12530

Mathematics

2 answers:

Margaret [11]2 years ago

8 0

Answer:

1530 < 12530

Step-by-step explanation:

i12530 is a bigger number than 1530

Alla [95]2 years ago

4 0

Answer:

what statement?

You might be interested in

In ΔEFG, the measure of ∠G=90°, the measure of ∠F=38°, and FG = 6.7 feet. Find the length of EF to the nearest tenth of a foot.

Verizon [17]

Answer:

8.5

Step-by-step explanation:

4 0

3 years ago

Find the domain and range

tresset_1 [31]

Domain: all real numbers
Range: y>-3

4 0

2 years ago

Shelby found a nice 2 bedroom apartment for rent for per month What should her monthly income be to afford this apartment?

Kryger [21]

Is it any answer choices?

8 0

2 years ago

Janine is saving money to buy a car. She has a total of $1400 left to save, and she plans to save a certain percentage of $1400

shusha [124]

Answer:

August=$350

September=$560

October=$210

November= $280

Step-by-step explanation:

Total amount left to save $1400.

We calculate the amount save each mount since we are already given the percentages.

For the month of August she saves 25% of $1400, we convert the percentage to equivalent cash

$\frac{25}{100}*1400\\=350$

for the month of August, she saved $350,

Next For the month of September she saves 40% of $1400, we convert the percentage to equivalent cash

$\frac{40}{100}*1400\\=560$

for the month of September, she saved $560,

Next For the month of October she saves 15% of $1400, we convert the percentage to equivalent cash

$\frac{15}{100}*1400\\=210$

for the month of October, she saved $210,

total amount saved by October = $350+$560+$210=$1120

Amount saved by November=1400-1120=$280

5 0

2 years ago

The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.

slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is; 1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0

1 year ago