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snow_lady [41]
3 years ago
7

Which of the following is true for this table? Will give brainliest for correct answer.

Mathematics
1 answer:
marshall27 [118]3 years ago
6 0

It could be seen from the table that when x is 2, the y value is 0. Thus, it can be concluded that the x intercept is (2,0)

The correct answer is B

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Answer: are you sure you did ask a question instead of answer it, I’m answering yours like this. Maybe you hit something different. You get points when you answer people. And you use points when you ask a question

Step-by-step explanation:

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WILL GIVE BRAINLIEST!!<br><br> please help meee the question is in the picture
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The answer is 6cm

Step-by-step explanation:

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3 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Can someone help me with exercise 121?
yanalaym [24]
It would be
(X^4+2X^2) -119(X^2-2X) then you would simplify
X^4+2X^2-119X^2-2X
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X^4+117X^2-2X=0
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8 0
3 years ago
A Right Triangle (ABC) has sides measuring 3 inches and 4 inches. The hypotenuse is 5 inches. A similar right triangle (A'B'C')
fenix001 [56]

Answer:

The length of hypotenuse is 12.5

Step-by-step explanation:

First 7.5 x 7.5 = 56.25

Then 10 x 10 = 100

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