Establish two right triangles, both with the height of the pole, h.
Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.
Apply Pytagora's equation to both triangles.
1) h^2 = 7^2 - x^2
2) h^2 = 8^2 - (6-x)^2
Eaual 1 to 2
7^2 - x^2 = 8^2 - 6^2 +12x -x^2
12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21
x = 1.75
Substitue x-value in 1
h^2 = 49 - (1.75)^2 = 45.94
h = sqrt(45.94) = 6.78
Answer: option d.
Answer:
X=3
Step-by-step explanation:
Answer: QF = 5
Step-by-step explanation:
We know that if a triangle has a centroid, the ratio of the longer segment to shorter segment is 2:1. We can set up a proportion 
, where x is the length of QF. By cross multiplying and dividing, you get x = 5 or QF = 5.
The surface area is 46. Use 2(lw x lh x wh)
