Answer:
Therefore, the conclusion is valid.
The required diagram is shown below:
Step-by-step explanation:
Consider the provided statement.
Premises: All good students are good readers. Some math students are good students.
Conclusion: Some math students are good readers.
It is given that All good students are good readers, that means all good students are the subset of good readers.
Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.
Therefore, the conclusion is valid.
The required diagram is shown below:
Answer:
6 13/14
Step-by-step explanation:
Convert 2/7 to 4/14 by multiplying both 2/7 by 2/2, to have a common denominator, then add your mixed numbers.
2/7 x 2/2 = 4/14
4/14 + 9/14 = 13/14
4 + 2 = 6
6 13/14
Answer:
212,214,216
Step-by-step explanation:
n+n+2+n+4=642
add the n's and 2 and 4
3n+6=642
subtract 6 from both sides
636 divided by 3
you get 212 then add 2 twice.
Easy peasy
the bit where it says
D={something}
those are the numbers you should input for x to get y values
3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)
x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another
x=0
y=-3/5(0)-4
y=-4
(0,-4) is another
x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)
points are (-10,2), (-5,-1), (0,-4), (5,-7)
4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)
x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)
x=0
y=(0)^2-3
y=-3
(0,-3)
x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)
x=2
y=(2)^2-3
y=4-3
y=1
(2,1)
the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)
see graph below
