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bearhunter [10]
3 years ago
10

What is an ecosystem? Please use your own words

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
7 0

Answer:

An ecosystem is a community of species.

Explanation:

i hope this helps i tried^^

Elena-2011 [213]3 years ago
7 0

Answer:Its a specific place were specific animals live.

Explanation:

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Help please! its cell functions
babunello [35]

Answer:

Hello There!!

Explanation:

The answer is the last option: cells use oxygen to release energy from food.

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5 0
3 years ago
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In an experiment, what is the purpose of the control group?
Burka [1]

A control group is the comparison group that helps to "make sure your experiment works." A control group is separated from the rest of the experiment and nothing happens to it kinda like a controlled variable.  Controlled variables are the variables in a experiment that remains the same for example a temperature, time, type of products, etc..

Hope this helps!

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3 years ago
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When an electric circuit is created, electrons begin to move where?
Sergeu [11.5K]

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3 0
3 years ago
Use the reaction to answer the question.
ki77a [65]

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The product expected is 10CO2 + 4H2O

7 0
3 years ago
The argon atoms are excited into an excited state before emitting the 488.0 nm laser. It is known that the energy of the first i
Jobisdone [24]

Answer:

Explanation:

Given that:

The argon atoms are excited into an excited state before emitting the 488.0 nm laser.

the energy of the first ionization energy of argon is 1520 kJ mol-1.

SInce 1 eV = 96.49 kJ/mol

Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV

=  15.75 eV

To find where  the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.

E = \dfrac{hc}{\lambda}

E  = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  =4.057 \times 10^{-19} \ J

Converting Joules (J) to eV ; we get,

E  =\dfrac{4.057 \times 10^{-19}}{1.6 \times 10^{-19}}

E = 2.53 eV

The energy levels of the first exited state = -13.223 eV

8 0
3 years ago
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