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zepelin [54]
3 years ago
9

_____ energy is required to start a reaction

Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer: Activation

Explanation:

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What is the equilibrium constant of a reaction
Svetach [21]

Homogeneous Reactions. At equilibrium, the rate of the forward and reverse reaction are equal, which is demonstrated by the arrows. The equilibrium constant, however, gives the ratio of the units (pressure or concentration) of the products to the reactants when the reaction is at equilibrium.

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what mass of small stones would be needed to make the strongest concrete? give a reason for your awnser.
VikaD [51]

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For a good consert mix aggregate needed to the clean hard strong partical free of absorb chemicals or coating clay and other fine materials

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3 years ago
Which object has stored gravitational potential energy
kakasveta [241]

Answer:a lightbulb burning

Explanation:

Apex

5 0
3 years ago
Read 2 more answers
The molarity (M) of an aqueous solution containing 29.8 g of sucrose, C12H22O11, in 120 mL of solution is:
Rama09 [41]

Answer:

0.726 mol·L⁻¹

Step-by-step explanation:

c = moles/litres

=====

Moles = 29.8 × 1/342.30

Moles = 0.087 06 mol

=====

Litres = 120 × 1/1000

Litres = 0.120 L

=====

c = 0.087 06/0.120

c = 0.725 mol·L⁻¹


5 0
3 years ago
15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up
maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

3 0
3 years ago
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