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zepelin [54]
3 years ago
9

_____ energy is required to start a reaction

Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer: Activation

Explanation:

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The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol. How much energy is produced by burning 0.8210 g
bazaltina [42]

The energy produced by burning : -32.92 kJ

<h3>Further explanation</h3>

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The enthalpy and heat(energy) can be formulated :

\tt \Delta H=\dfrac{Q}{n}\rightarrow n=mol

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol.

The energy released for 0.8210 g of naphthalene :

\tt Q=\Delta H\times n\\\\Q=-5139.6~kJ/mol\times \dfrac{0.8210~g}{128.17~g/mol}~\\\\Q=-32.92~kJ

3 0
2 years ago
Help, and fast! I really need an answer to this.
Travka [436]

Answer:

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8 0
3 years ago
Which is a characteristic of a strong base
Lubov Fominskaja [6]

Answer:

Explanation:

The strong bases have following properties:

1. In solution, strong bases ionize fully.

2. On dissolving the strong bases in water they produce all hydroxide ion which they have.  

3. For strong bases the value of equilibrium constant (Kb  ) is large.

4. In general the strong base ionizes completely means concentration of ions are greater means conductivity also greater.

5. For strong bases the value of equilibrium constant (Kb) is large, thus the value of dG0 is very large negative number.

6 0
3 years ago
2.41 x 10^2 Cm to meters
Assoli18 [71]

We know that there are 100 cm in 1 m, so we can use this to convert to meters:

(\frac{2.41x10^{2}cm}{1})*(\frac{1m}{100cm} )=2.41m

Therefore we know that 2.41x10^{2} cm is equal to 2.41 m.

8 0
3 years ago
Read 2 more answers
112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.
dolphi86 [110]

<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       .....(1)

Given mass of aluminium carbide = 112 g

Molar mass of aluminium carbide = 143.96 g/mol

Putting values in equation 1:

\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol

For the given chemical reaction:

2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)

By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = \frac{12}{2}\times 0.778=4.668 mol of water

Given mass of water = 174 g

Molar mass of water = 18 g/mol

Putting values in equation 1:

\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

Hence, 4.999 moles of excess reactant will be left over.

8 0
2 years ago
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