4 years ago

Which of the following are solutions to the equation below?

Mathematics

2 answers:

NemiM [27]4 years ago

4 0

Answer:

C and D

Step-by-step explanation:

Given

(3x - 5)² = 19 ( take the square root of both sides )

3x - 5 = ± $\sqrt{19}$ ( add 5 to both sides )

3x = ± $\sqrt{19}$ + 5 ( divide both sides by 3 )

x = $\frac{+/-\sqrt{19}+5 }{3}$

x = $\frac{-\sqrt{19}+5 }{3}$ → C

x = $\frac{\sqrt{19}+5 }{3}$ → D

Dennis_Churaev [7]4 years ago

3 0

Answer:

C and D

Step-by-step explanation:

You might be interested in

In the 30-60-90 triangle below, side s has a length of length of and side r has a

NemiM [27]

I'M NOT SURE

Step-by-step explanatioI'M NOTN SURE

3 0

3 years ago

Read 2 more answers

Solve for w. 0.05w = 15

steposvetlana [31]

In order to find the value first multiply both sides by 100 to simplify the equation:
0.05w*100=15*100
5w=1500
Next, divide both sides of the equation by 5:
5w/5=1500/5
w=300
The final solution is w=300!

Hope i could help.
have a great day

4 0

3 years ago

Read 2 more answers

Round each mixed number to the nearest whole number. Then, estimate the sum. 14/11/12+3/1/6

yanalaym [24]

$14\11\12 + 3\1\6$

4 0

3 years ago

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

2 years ago

Draw a parallelogram that has side lengths of 2 inches and 1 inch and which has angle measures of 120° and 60°. Label all measur

ANEK [815]

Answer:

see attached

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers