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AleksandrR [38]
2 years ago
12

Round each mixed number to the nearest whole number. Then, estimate the sum. 14/11/12+3/1/6

Mathematics
1 answer:
yanalaym [24]2 years ago
4 0

14\11\12 + 3\1\6

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Write each rate as a unit rate. $2 for 5 cans of soup.
Len [333]
If you would like to write each rate as a unit rate, you can do this using the following steps:

$2 ... 5 cans of a soup
$1 ... x cans of a soup = ? 

2 * x = 5 * 1
2 * x = 5
x = 5 / 2
x = 2.5 cans of a soup per $1

$2 ... 5 cans of a soup
$x = ? ... 1 can of a soup

2 * 1 = 5 * x
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3 years ago
Ted jogged a total of 11.2 miles in 4 days. He jogged the same distance each day
marta [7]

Answer:

Part A: 2.8 miles

Part B: 16.8 miles

Step-by-step explanation:

First, solve for how many miles Ted jogged in 1 day:

Variable x = number of miles

11.2/4 = x/1

Cross multiply

11.2 × 1 = 4 × x

11.2 = 4x

Divide both sides by 4

2.8 = x

He jogged 2.8 miles every day.

To find how many miles Ted would jog in 6 days, simply multiply his miles per day by the number of days he will jog:

2.8 miles × 6 days = 16.8 miles in 6 days

3 0
3 years ago
What is 63÷9+40-35÷7 pls help
Murljashka [212]
63/9 + 40 - 35/7 =
7 + 40 - 5 =
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6 0
3 years ago
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Write down the size of angle ABC give a reason your answer ​
FrozenT [24]
ABC = 180 degrees because a triangle is always equal to 180degree
3 0
3 years ago
a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t
Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

Step-by-step explanation:

Given:

Circumference of the circle = 2\pi r

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}

Now we know that;

side of the square= diameter of the circle

side of the square = 2r

Now Perimeter of the square is given by 4 times length of the side.

P=4\times 2r =8r

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}

But \frac{dr}{dt} =\frac{3}{\pi}

So we get;

\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\  in/sec

Hence The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

5 0
3 years ago
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