Put the marked magnet up to each side of the unmarked one. if they attract they are opposite -north attracts south, south attracts north- if they repel -forcefully push away- from each other they are the same -north and north, or south and south. once you have done that you can label the poles correctly.
you can use stoichiometry which is taking the number in from of each substance and using it as a molar ratio(ones that don't have a number actually have a 1 in front
so 2AgNO3 + 1 Zn -> 2 Ag + Zn (NO3)2
The ratio is of moles of Zn to moles of Silver is 1:2 so for every 1 mole of Zn there's 2 moles of Ag
1.3 × 2 = 2.6 moles of Ag are made
In the electrolysis of molten BaI₂, the product forms at the cathode Barium metal (Ba).
First ionic bonds in this salt are separated because of heat:
BaI₂(aq) →
(aq) + I⁻(aq).
Reaction of reduction at cathode(-):
(aq) + 2e⁻ → 2Ba(s)
turns into Ba metal.
Reaction of oxidation at anode(+):
2I⁻(aq) → I₂(g) + 2e⁻.
So I⁻ turns into I₂(g)
The anode is positive and the cathode is negative.
In chemistry, the type of process in which decomposition of a chemical substance occurs due to the flow of electricity through the substance is generally known as the electrolysis process. Usually, the electrolysis process becomes in an arrangement in which one electrode of the cathode and one electrode of the anode are present.
In chemistry and production, electrolysis is a technique that makes use of direct electric present-day (DC) to power an otherwise non-spontaneous chemical response.
Electrolysis is commercially crucial as a degree inside the separation of factors from clearly going on sources including ores the usage of an electrolytic cell.
To learn more about the electrolysis please click on the link : brainly.com/question/24063038
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There are 70.90g of Cl2 in 1 mol (because 35.45g Cl in one mol). So 77.1g/70.9g≈1.0874 mol.
Answer:
35.3 g
Explanation:
Step 1: Given data
Number of atoms of aluminum: 7.90 × 10²³ atoms
Step 2: Calculate the number of moles corresponding to 7.90 × 10²³ atoms of aluminum
We will use Avogadro's number: there are 6.02 × 10²³ atoms of aluminum in 1 mole of atoms of aluminum.
7.90 × 10²³ atoms × (1 mol/6.02 × 10²³ atoms) = 1.31 mol
Step 3: Calculate the mass corresponding to 1.31 moles of aluminum
The molar mass of Al is 26.98 g/mol.
1.31 mol × 26.98 g/mol = 35.3 g