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Inessa [10]
2 years ago
11

57.A cofactor is a(an)

Chemistry
1 answer:
Rudik [331]2 years ago
3 0

A cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts (option E).

<h3>What is a cofactor?</h3>

A cofactor in biochemistry is a molecule that binds to and regulates the activity of a protein.

A cofactor is a metal or coenzyme responsible for the functioning of an enzyme and must be present.

Therefore, a cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts.

Learn more about cofactors at: brainly.com/question/13004767

#SPJ1

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Ethanol melts at -114 °C and boils at 78 °C.
Aliun [14]
A) solid
b)liquid
c)liquid
d)gas
5 0
3 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
I need helpppppppp, please
NNADVOKAT [17]

Explanation:

cant answer without context

8 0
2 years ago
38 points!! &gt;:D
Sav [38]

Answer: which*

Explanation:

8 0
3 years ago
Read 2 more answers
HELP FAST 100 PTSCalculate the amount of heat needed to convert 100.0 g of liquid water at 25 °C to water at 100 °C.
Alex Ar [27]

Answer:

31,380 Joules

Explanation:

Given Data:

Mass = m = 100 g

Temperature 1 = = 25 °C

Temperature 2 = = 100 °C

Specific Heat Constant = c = 4.184

Change in Temp. = ΔT = 100 - 25 = 75 °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (100)(4.184)(75)

Q = 31, 380 Joules

Hope this helped!

~AH1807

4 0
3 years ago
Read 2 more answers
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