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harina [27]
3 years ago
14

If a translation of the figure above is plotted 7 units to the right and 2 units up, where will point A' be located on the new f

igure?
A. (7,2)
B. (-12,3)
C. (12,3)
D. (2,7)

Mathematics
1 answer:
pychu [463]3 years ago
6 0
D. because you just count 7 units to the right and then 2 units up.
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54.628 rouned to rhe nearst tenth
likoan [24]
Round down to 54.6 because it is 5 or less.

8 0
3 years ago
Read 2 more answers
What is the product of any integer and -1
mixas84 [53]

Answer:

The negative counterpart

Step-by-step explanation:

x * -1 = -x

For example, 3 * -1 = -3

Hope this helps.

5 0
3 years ago
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The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi
lara [203]

Answer:

a) 33.33%)

b) 135 minutes

c) 8.66 min

d) 50%

Step-by-step explanation:

a) the probability for a uniform distribution is

P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values

therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)

P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)

b) the mean (expected value) for a uniform probability distribution is

E(X) = (c+d)/2 = (120+150)/2 = 135 minutes

c)  the standard deviation for a uniform probability distribution is

σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²

σ = √75 min² = 8.66 min

b) following the same procedure as in a)

P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)

4 0
3 years ago
Solve x2 – 2x – 15 = 0 using the zero product property.
Greeley [361]
The roots or the Zeros of <span>x^2 – 2x – 15 = 0 would be 
C. x=5, -3</span>
3 0
4 years ago
For the equation given below, evaluate y′ at the point (−2,2)<br> xe^y−4y=2x−4−2e^2
jeka94
Implicit differentiation
chain rule is important here

I'll show the steps partially
e^y+xe^yy'-4y'=2
xe^yy'-4y'=2-e^y
y'(xe^y-4)=2-e^y
y'=\dfrac{2-e^y}{xe^y-4}
now evaluate for (-2,2)
x=-2 and y=2
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{e^2-2}{2e^2+4}
that's it, simplest form
3 0
4 years ago
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