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2 years ago

If you answer this question I will mark you brainliest

Mathematics

2 answers:

Studentka2010 [4]2 years ago

6 0

$\large\huge\green{\sf{Answer:-}}$

in ∆ABD and CND

AD = DC. (given)
AB= BC (given)
DB= DB. (common side)

∴ ∆ABD ≅ ∆ CND (by S SS congruent condition)

GaryK [48]2 years ago

4 0

Answer:

Yes they are congruent

they are congruent by SSS rule that is Side Side Side rule

AD = CD (given side) in the question itself

AB = CB (given side) in the question itself

Db = BD (common side)

thats why by SSS rule they are congruent

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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2 years ago

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Collin is building a deck on the back of his house. He has enough lumber for the deck to be 144 square feet. The length should b

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