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2 years ago

We need a rock garden work a perimeter of 18ft area 18ft what is the length and width

Mathematics

2 answers:

WINSTONCH [101]2 years ago

5 0

Answer:

P = perimeter

A = area

l = lenght

w = width

P = 2 x l + 2 x w

A = l x w

18 ft = 2 x l + 2 x w

18 ft² = l x w

Input l = 6 ft w = 3 ft

18 ft = 12 ft + 6 ft = 18 ft

18 ft² = 6 ft x 3 ft = 18 ft²

Answer:

l = 6 ft

w = 3 ft

ivanzaharov [21]2 years ago

5 0

Step-by-step explanation:

let the length be l and breadth be b.

perimeter = 2(l +b)

18 = 2(l+ b)

9 = l+ b

b = 9-l .... eq - 1

area = l× b

18 =l ( 9-l)

18 = 9l - l²

l²- 9l + 18 = 0

l ² -3l - 6l +18 = 0

l (l -3) -6 ( l -3) = 0

(l - 6 ) ( l-3) = 0

length (l). = 6 or 3 ft

then breadth = 9-l = 9-3 or 9-6

= 6 or 3 ft

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hope this will be helpful to you ☺️.

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3 years ago

A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s

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Answer:

$310\text{ feet and }210\text{ feet}$

Step-by-step explanation:

GIVEN: A farmer has $520 \text{ feet}$ of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is $310 \text{ feet}$ .

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be $x$ and $y$

perimeter of rectangular pen $=2(x+y)=520\text{ feet}$

$x+y=260$

$y=260-x$

area of rectangular pen $=\text{length}\times\text{width}$

$=xy$

putting value of $y$

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to maximize $\frac{d \text{(area)}}{dx}=0$

$260-2x=0$

$x=130\text{ feet}$

$y=390\text{ feet}$

but the dimensions must be lesser or equal to than that of barn.

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width of rectangular pen $=210\text{ feet}$

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Step-by-step explanation:

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We need a rock garden work a perimeter of 18ft area 18ft what is the length and width​

We need a rock garden work a perimeter of 18ft area 18ft what is the length and width