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yuradex [85]
3 years ago
7

10 times as many as 1 hundred is _____ hundreds or________ thousand.

Mathematics
2 answers:
Alchen [17]3 years ago
5 0
So if 10 times then 48=23
vampirchik [111]3 years ago
5 0
Ten hundreds, or one thousand are the correct answers.
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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

cot\angle AOB = \dfrac{Base}{Perpendicular}

\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
3 years ago
find the slope of the line through the given pair of points, if possible. Based on the slope, indicate whether the line through
Nat2105 [25]
Easy peasy
slope=(change in rise)/(change in run)
aka
slope between points (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1) since y is rise/up and x is run/leftright

points

(-7,-9) and (-5,-8)
x1=-7
y1=-9
x2=-5
y2=-8
remember minusing a negative means addin a positive
slope=(-8-(-9))/(-5-(-7))=
(-8+9)/(-5+7)=1/2

slope=1/2

positive slopes go from bottom left to top right

since it is less than 1
it is more horizonal than vertical




4 0
3 years ago
3(7x+4)-x as an infinite equation
Sidana [21]

Answer: 20x+12

Step-by-step explanation:

Distribute the three: 3(7x+4) will be changed to 21x+12-x

Next group like terms, -x+21x=20x

The new equation will be 20x+12

3 0
3 years ago
Read 2 more answers
Which inequality corresponds<br>to the following graph?​
alexira [117]
The first one x is greater than and equal to 34
4 0
3 years ago
What two parts of a regular polygon are congruent?
scoray [572]
I guess sides and angles !
6 0
3 years ago
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