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Arlecino [84]
2 years ago
7

What is the least common multiple of 4 and 6? Enter your answer in the box.

Mathematics
2 answers:
natta225 [31]2 years ago
8 0

Start out by looking for the prime factors of BOTH numbers (4,6)

2*2=4 


2*3=6

2^2*3^1=12

12 is the LCM

Schach [20]2 years ago
5 0
12 is the least common multiple
You might be interested in
Estamate 12871+6281+5146 by first rounding each number to the nearest thousand.
Pie
12,871 rounded to nearest thousand = 13,000.

6281 rounded to nearest thousand = 6,000.

5146 rounded to nearest thousand = 5,000.

In total, 13,000 + 6,000 + 5,000 = 24,000.
4 0
3 years ago
PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​
AysviL [449]

Answer:

Step-by-step explanation:

The first choice is correct

The rate is 20 per dog, thus we get the equation:

c= 20d

However the first dog is free, so the equation becomes

c = 20(d - 1)

And he also has a walking fee of 85 dollars and thus the equation becomes

c= 85 + 20(d-1)

5 0
2 years ago
Avoiding an accident while driving can depend on reaction time. Suppose that reaction time, measured from the time the driver fi
Nadya [2.5K]

Answer:

2.5% of drivers have a reaction time more than 2.14 seconds

16% of drivers have a reaction time less than 1.78 seconds

84% of drivers have a reaction time less than 2.02 seconds

Step-by-step explanation:

The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

In this problem, we have that:

Mean = 1.9s

Standard deviation = 0.12

What percentage of drivers have a reaction time more than 2.14 seconds?

2.14 = 1.9 + 2*0.12

So 2.14 is two standard deviations above the mean.

Of the 50% of the measures above the mean, 95% are within 2 standard deviations of the mean, so, below 2.14. The other 5% is above.

0.05*0.5 = 0.025

2.5% of drivers have a reaction time more than 2.14 seconds

What percentage of drivers have a reaction time less than 1.78 seconds?

1.78 = 1.9 - 0.12

So 1.78 is one standard deviation below the mean.

Of the 50% of the measures that are below the mean, 68% are within one standard deviation of the mean, that is, greater than 1.78.

100 - 68 = 32

0.32*50 = 0.16

16% of drivers have a reaction time less than 1.78 seconds

What percentage of drivers have a reaction time less than 2.02 seconds?

2.02 = 1.9 + 0.12

So 2.02 is one standard deviation above the mean.

Of the measures that are below the mean, all are below 2.02.

Of those that are above, 68% are below 2.02.

0.5 + 0.68*0.5 = 0.84

84% of drivers have a reaction time less than 2.02 seconds

5 0
3 years ago
Can an expert help with this
SVEN [57.7K]

The formula of an area of a circle:

A_O=\pi r^2

We have

r = 1.8 m

π ≈ 3.14

Substitute:

A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2

7 0
2 years ago
Based on the given information, which conjecture is invalid?
a_sh-v [17]
Valid based on the given information<span>. If not, write </span>invalid<span>. ... So, the statement is </span>invalid<span>. Determine .....disprove a </span>conjecture<span> reached using inductive or deductive</span><span> .</span>
3 0
3 years ago
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