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gizmo_the_mogwai [7]
3 years ago
12

What two variables are likely to have a negative correlation

Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer:

<u><em>Negative Correlation</em></u>

The variable x - value increases as y- value decreases is called negative correlation.

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Negative correlation:-    

The negative correlation is a relation between two variables such that they are part of a function in which depends and independent variables move in different directions in terms of value.

<u><em>Positive correlation</em></u>

The variable x - value increases as y- value increases is called positive correlation.

<u><em>Negative Correlation</em></u>

The variable x - value increases as y- value decreases is called negative correlation.

<u><em>No correlation </em></u>

There is no pattern  between two variables

there is no connect between two variables is called No - correlation

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Vadim26 [7]

Answer:

B. x

Step-by-step explanation:

The answer would be graph x. A function must be that one x value should only have one y value. graph w doesn't work since when you plug in 0, you get two y's. same thing with z. Y doesn't work since at x value of 3, it curves back so x value 2 has 2 y's. X is the only one that each x value has only one y.

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What is the percent equivalent of 11.21? Select one: A. 112.1% B. 0.1121% C. 1,121% D. 11.21%
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4 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
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x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
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0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
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y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
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A=<4.60,7.20>
b=<5.10,2.70>
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Answer:

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Step-by-step explanation:

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